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Keith_Richards [23]
1 year ago
15

What error, if any, would the calculated density of the solid have if the material had a hollow center?.

Chemistry
1 answer:
dolphi86 [110]1 year ago
7 0

The error that would make the calculated density of the solid have if the material had a hollow center is that the calculated density would be low, because the volume would be incorrectly measured high.

<h3>What is density?</h3>

The measure of how densely a material is packed together is called density. As the mass per unit volume, it has that definition. Density Formula: = m/V, where is the density, m is the object's mass, and V is its volume. Density Symbol: D.

If a substance had a hollow center, its volume would be high and its density would be low.

Therefore, the error that would make the calculated density of the solid have if the material had a hollow center is that the calculated density would be low, because the volume would be incorrectly measured high.

Learn more about density on:

brainly.com/question/1354972

#SPJ1

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Calculate the pH for each of the cases in the titration of 25.0 mL of 0.180 M pyridine, C 5 H 5 N ( aq ) with 0.180 M HBr ( aq )
Oxana [17]

Answer:

Explanations

Calculate the pH for each of the following cases in thetitration of 25.0 mL of 0.100 M pyridine, C5H5N(aq) with 0.100 MHBr(aq):

a.Before and addition of HBr

b.After addition of 12.5ml HBr

c.After addition of 15ml HBr

d.After addition of 25ml HBr

e.After addition of 33ml HBr

SOLUTION ;;;

Kb of pyridine =1.5*10^-9

a)let the dissociation be x.so,

kb=x^2/(0.1-x)

or 1.5*10^-9=x^2/(0.1-x)

or x=1.225*10^-5

so,

[OH-]=1.225*10^-5

so,

pOH=-log([OH-])

so pH=9.088

b)now this will effectively behave as a buffer

pKb=8.82

so pOH=pKb+log(salt/acid)

=8.82+log((12.5*0.1)/(25*0.1-12.5*0.1))

=8.82

so pH=14-pOH

=5.18

c)again using the same equation as the above,

pOH=pKb+log(salt/acid)

=8.82+log((15*0.1)/(25*0.1-15*0.1))

=9

so pH=14-9

=5

d)now the base is completely neutralised.so,

concentration of the salt formed=0.1/2

=0.05 M

so,

pH=7-0.5pKb-0.5log(C)

=7-0.5*8.82-0.5*log(0.05)

=3.24

e)concentration of H+=(33*0.1-25*0.1)/(33+25)

=0.01379

so pH=-log(0.01379)

=1.86

4 0
3 years ago
Read 2 more answers
True or false: mole fractions are intensive properties g
wolverine [178]
True I think sorry if wrong!

3 0
3 years ago
To prepare 1.00 L of 14g BaCl2, what Molarity would it be?​
nikklg [1K]

Answer:

0.067 M  

Explanation:

Given data:

Volume of solution = 1.00 L

Mass of BaCl₂ = 14 g

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will calculate the number of moles first.

Number of moles = mass/ molar mass

Number of moles = 14 g/ 208.23 g/mol

Number of moles = 0.067 mol

Now we will calculate the molarity.

Molarity = 0.067 mol / 1.00 L

Molarity  = 0.067 M    ( mol/L=M)

6 0
3 years ago
Help….? Anyone? It’s a test. 99 points
Crazy boy [7]
Answer:

Cyanobacterium


Explanation:

“Cyanobacterium” is the correct answer, as it has the kingdom bacteria in its name.
7 0
2 years ago
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G an aqueous solution contains 0.10 m naoh. the solution is ________. an aqueous solution contains 0.10 m naoh. the solution is
Bad White [126]
Answer is "basic".

NaOH is basic solution and it is a colorless solution. Due to the concentraion is 0.1 M, the solution contains 0.1 M of OH⁻ ions because NaOH fully dissociates into its ions as OH⁻ and Na⁺ in water.

NaOH → OH⁻ + Na⁺

pOH = -log[OH⁻]
        = -log(0.1)
        = 1
pH = 14 - pOH
     = 14 - 1
     = 13

Hence, pH of this G solution is 13 which is highly basic.

5 0
3 years ago
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