Answer: option B. 0.59
Explanation:Please see attachment for explanation
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
Soil temperature and <span>water content</span>
Explanation:
As the given data is as follows.
Height, H = 150 feet
Heat gain = 30,000 BTU/hr, and Heat loss = 25000 BTU/hr
m = mass of water heated = 700 gallons = 5810 lbs
is the heat capacity of water = 1 BTU/lb
(given)
= temperature difference = 
Heat energy required to heat 700 gal can be calculated as follows:
Heat Required = 
Thus, water rises till
.