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Mila [183]
2 years ago
6

The electric current in a wire is 1.5A. How many electrons flow past a given point in a time of 2s?

Physics
1 answer:
kipiarov [429]2 years ago
5 0

Answer:

The amount of electrons that flow in the given time is 3.0 C.

Explanation:

An electric current is defined as the ratio of the quantity of charge flowing through a conductor to the time taken.

i.e           I = \frac{Q}{t} ...................(1)

It is measure in Amperes and can be measured in the laboratory by the use of an ammeter.

In the given question, I = 1.5A, t = 2s, find Q.

From equation 1,

            Q = I × t

                = 1.5 × 2

               = 3.0 Coulombs

The amount of electrons that flow in the given time is 3.0 C.

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Answer:

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}} (1)

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L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity


In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

f=\frac{N}{t}=\frac{20}{35.5 s}=0.563 Hz

And the period is the reciprocal of the frequency:

T=\frac{1}{f}=\frac{1}{0.563 Hz}=1.776 s

And by using this into eq.(1), we can find the value of g:

g=\frac{4 \pi^2 L}{T^2}=\frac{4 \pi^2 (0.600 m)}{(1.776 s)^2}=7.50 m/s^2

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How does emission spectra occur?
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3 years ago
Two animals that can be found at the Grand Canyon include the Abert’s and Kaibab squirrels. The Abert’s squirrel is found at the
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D. <span>When placed together in pairs for study, no pair of Abert's squirrel and Kaibab squirrel result in offspring.</span>
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3 years ago
A uniform-density 7 kg disk of radius 0.21 m is mounted on a nearly frictionless axle. Initially it is not spinning. A string is
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Answer:

\omega = 22.67 rad/s

Explanation:

Here we can use energy conservation

As per energy conservation conditions we know that work done by external source is converted into kinetic energy of the disc

Now we have

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now we know that work done is product of force and displacement

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now for moment of inertia of the disc we will have

I = \frac{1}{2}mR^2

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5 0
2 years ago
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