Answer:
The energy that will go will for thermal store of the surroundings is 20 J.
Explanation:
Given;
kinetic of the thrown ball, K.E₁ = 50 J
kinetic energy used to move the target, K.E₂ = 30 J
The excess energy that will go will for thermal store of the surroundings;
ΔK.E = K.E₁ - K.E₂
ΔK.E = 50J - 30J
ΔK.E = 20 J
Therefore, the energy that will go will for thermal store of the surroundings is 20 J.
Answer:
The maximum current which can flow through a fuse without melting it, is called its rating. ... If current higher than 8 A flows through the fuse, it would melt and circuit gets broken. ... Hence, fuse acts as a safety device
Answer:
a)
and
b) t = γt', so it is 8.35 s.
Explanation:
a) The equation of Lorentz transformations is given by:
x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.
- x' = 0
- t' = 5.00 s
- u =0.800 c, c is the speed of light 3*10⁸ m/s
![\gamma=\frac{1}{\sqrt{1-(u/c)^{2}}}](https://tex.z-dn.net/?f=%5Cgamma%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%28u%2Fc%29%5E%7B2%7D%7D%7D)
![\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}](https://tex.z-dn.net/?f=%5Cgamma%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%280.800c%2Fc%29%5E%7B2%7D%7D%7D)
![\gamma=\frac{1}{\sqrt{1-(0.800)^{2}}}](https://tex.z-dn.net/?f=%5Cgamma%3D%5Cfrac%7B1%7D%7B%5Csqrt%7B1-%280.800%29%5E%7B2%7D%7D%7D)
![\gamma=1.67](https://tex.z-dn.net/?f=%5Cgamma%3D1.67)
![x=1.67(0+0.800c*5.00)](https://tex.z-dn.net/?f=%20x%3D1.67%280%2B0.800c%2A5.00%29)
![x=2*10^{9} m](https://tex.z-dn.net/?f=%20x%3D2%2A10%5E%7B9%7D%20m)
Now, to find t we apply the same analysis:
but as x'=0 we just have:
b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.
I hope it helps you!
Answer:
250 m/min down the road
Explanation:
Velocity is equivalent to speed but it considers the direction of the object. Velocity is also calculated by dividing the distance travelled by time. Therefore,
where d and t are distance and time respectively. Given that d is given as 350 m and t is 1.4 s then by substitution
and the direction is down the road.
Velocity is 250 m/min down the road
I can help you do them for yourself :)