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Naya [18.7K]
4 years ago
9

What happens if someone walks between you and the heater? Can you still feel its warmth?

Physics
2 answers:
Pie4 years ago
6 0
No, for that moment
Vikentia [17]4 years ago
5 0

Answer:

When someone walks between you and a heater, you can't feel the warmth because when somebody walks past, you feel a cold breeze while they walk past and it takes a second to warm up again.

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What types of electromagnetic radiation that reaches earths surface
AlladinOne [14]
<span>The electromagnetic emissions from solar flares aren't much different from those produced by the rest of the sun, but do include somewhat higher levels of soft x-rays and low-energy gamma rays. These emissions are of course dwarfed by the normal output of the sun, and are of such low density by the time they reach Earth that they have no discernible effect on organic matter. </span>
5 0
4 years ago
How far will a body move in 4 seconds if uniformly accelerated from rest at rate of 2m\sm\s​
Lubov Fominskaja [6]

Answer:

16 m

Explanation:

For an object in uniformly accelerated motion (=with constant acceleration), the distance covered by the body can be found by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

For the body in this problem,

u = 0 (it starts from rest)

a=2 m/s^2 is the acceleration

Substituting t = 4 s, we find the distance covered:

s=0+\frac{1}{2}(2)(4)^2=16 m

3 0
4 years ago
Groups of organs that work together to complete a process in the body are called:
Ainat [17]

Answer:

systems

Explanation:

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3 0
3 years ago
Read 2 more answers
If you enjoy teaching small or large glasses and being active every day which career would be a good fit for you
tino4ka555 [31]

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6 0
3 years ago
You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th
geniusboy [140]

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

7 0
3 years ago
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