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Naddika [18.5K]
3 years ago
10

Can someone please help

Chemistry
2 answers:
coldgirl [10]3 years ago
7 0

1. A metal is shiny

2. yes

that's all

Ratling [72]3 years ago
6 0

Answer:

1. c) shiny

2) True. Reactivity is a chemical property.

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The table tells us that the larger the diameter the shorter the period of rotation is
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Which of the following elements has the highest electronegativity?
Nastasia [14]

Answer: is c

Explanation:

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a. What is the definition of a mole? b. What is the abbreviation for mole? SARM c. How many particles are in one mole? d. What n
ycow [4]

Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

The mole of substance is the amount of substance that contain elementary particles as the number of atoms. the symbol of mole is mol. it is the SI unit of amount of substance. The number particles are ion one mole of substances is 6.022 × 10²³. The number of particles in one mole of substance is called as Avogadro's number.

Thus, Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

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7 0
1 year ago
How many electrons are in the highest occupied energy level of a neutral chlorine atom?
tino4ka555 [31]
There are seven electrons
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3 years ago
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PLEASE HELP ME SOLVE THIS.Thank you so much!
Tju [1.3M]

Answer: The coefficients for the given reaction species are 1, 6, 2, 3.

Explanation:

The given reaction equation is as follows.

Cr_{2}O^{2-}_{7} + Cl^{-} \rightarrow Cr^{3+} + Cl_{2}

Now, the two half-reactions can be written as follows.

Reduction half-reaction: Cr_{2}O^{2-}_{7} + 3e^{-} \rightarrow Cr^{3+}

This will be balanced as follows.

Cr_{2}O^{2-}_{7} + 14H^{+} + 6e^{-} \rightarrow 2Cr^{3+} + 7H_{2}O ... (1)

Oxidation half-reaction: Cl^{-} \rightarrow Cl_{2} + 1e^{-}

This will be balanced as follows.

6Cl^{-} \rightarrow 3Cl_{2} + 6e^{-} ... (2)

Adding both equation (1) and (2) we will get the resulting equation as follows.

Cr_{2}O^{2-}_{7} + 14H^{+} + 6Cl^{-} \rightarrow 2Cr^{3+} + 3Cl_{2} + 7H_{2}O

Thus, we can conclude that coefficients for the given reaction species are 1, 6, 2, 3.

6 0
2 years ago
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