Answer:
98.8
Explanation:
CsF + XeF6 --> CsXeF7
37.8g ................. ?g
37.8g CsF x (1 mol CsF / 151.9g CsF) x (1 mol CsXeF7 / 1 mol CsF) x (397.2g CsXeF7 / 1 mol CsXeF7) = 98.8g CsXeF7 .......... to three significant digits
Answer:
The correct answer is 10.939 mol ≅ 10.94 mol
Explanation:
According to Avogadro's gases law, the number of moles of an ideal gas (n) at constant pressure and temperature, is directly proportional to the volume (V).
For the initial gas (1), we have:
n₁= 1.59 mol
V₁= 641 mL= 0.641 L
For the final gas (2), we have:
V₂: 4.41 L
The relation between 1 and 2 is given by:
n₁/V₁ = n₂/V₂
We calculate n₂ as follows:
n₂= (n₁/V₁) x V₂ = (1.59 mol/0.641 L) x 4.41 L = 10.939 mol ≅ 10.94 mol
Answer:
В. No, because the mass of the reactants is less than the mass of the products.
Explanation:
Chemical equation:
NaBr + Cl₂ → 2NaCl + Br₂
The given equation is not balanced because number of moles of sodium and bromine atoms are less on reactant side while more on the product side.
There are one mole of sodium and one mole of bromine atom on left side of equation while on right side there are 2 moles of bromine and 2 moles of sodium atom are present. The number of moles of chlorine atoms are balanced.
Balanced chemical equation:
2NaBr + Cl₂ → 2NaCl + Br₂
Now equation is balanced. Number of moles of sodium , chlorine and bromine atoms are equal on both side.
Given :
Number of moles of CHF₃ is 1.7 .
Solution :
We know, 1 mole of any complex contains 6.022 × 10²³ molecules.
Let, 1.7 moles of CHF₃ contains n numbers of molecules.
So, n = 1.7 × 6.022 × 10²³ molecules
n = 10.2374 × 10²³ molecules
n = 1.0237 × 10²³ molecules
Hence, this is the required solution.