Answer:
Moles of H₂S needed = 6.2 mol
Moles of SO₂ produced = 6.2 mol
Explanation:
Given data:
Number of moles of O₂ = 9.3 mol
Moles of H₂S needed = ?
Moles of SO₂ produced = ?
Solution:
Chemical equation:
2H₂S + 3O₂ → 2SO₂ + 2H₂O
Now we will compare the moles of oxygen with H₂S.
O₂ : H₂S
3 : 2
9.3 : 2/3×9.3 = 6.2 mol
Now we will compare the moles of SO₂ with both reactant.
O₂ : SO₂
3 : 2
9.3 : 2/3×9.3 = 6.2 mol
H₂S : SO₂
2 : 2
6.2 : 6.2 mol
So 6.2 moles of SO₂ are produced.
.035 gallons equals 0.1324894 L
Answer:
The correct answer is that both molecular motion, pressure and temperature increase as volume reduces.
Explanation:
A reduction in volume changes the molecular motion, temperature and pressure of the system. When the volume of the container decreases, this causes the pressure to increase, the temperature to increase and the molecular motion to increase. This is because a liquid and a solid are incompressible, so by reducing the volume of a gas, the molecules increase their movement as the temperature of the system increases, which is due to the increased pressure applied to reduce the volume of the system.
Have a nice day!
Nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷nume smechere )(∂ⓓᗴηⓛ⫸⫷
Your answer is D. You're Welcome