All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
Hey there! :)
Answer:
A = 9/16 in².
Step-by-step explanation:
Use the formula A = s² to solve for the area where s = 3/4 in:
A = (3/4)²
A = 9/16 in².
Answer:
The best estimate is 32 out of 32 times, she will be early to class
Step-by-step explanation:
The probability of being early is 99% = 99/100 = 0.99
So out of 32 classes, the best estimate for the number of times she will be early to class will be;
0.99 * 32 = 31.68
To the nearest integer = 32
The answer is -14
Explanation:
x - 8 = 2x + 6
We move all term to the left
x - 8 - ( 2x + 6 ) = 0
We get rid of parentheses
x - 2x - 6 - 8 = 0
We add all the numbers together, and all the variables
-1x - 14 = 0
We move all terms containing x to the left, all other term to the right
-x = 14
x = 14/-1
x = -14
Answer:
Step-by-step explanation:
-31