Answer:
Step-by-step explanation:
B
2
3
Let the distance of two consecutive stones are x, x+1.
In ΔBCD, we have
tan60
o
=
x
h
⇒x=
3
h
.....(i)
In ΔABC, we have
tan30
o
=
x+1
h
⇒
3
1
=
x+1
h
⇒
3
h
+1=
3
h ......[from equation (i)]
⇒
3
2h
=1
⇒h=
2
3
km
solution
Answer:
39.275
Step-by-step explanation:
the diameter of the semicircle is 10
A semicircle is half a circle, and a quarter circle is 1/4 of a circle.
Perimeter of a semicircle is ¶d/2
= 3.142 x 10/2 = 3.142 x 5 = 15.71
For 2 semicircles that will be 15.71 x 2 = 31.42
For the quarter circle, perimeter is ¶d/4 = 3.142 x 10/4 = 3.142 x 2.5 = 7.855
Total perimeter = 31.42 + 7.855 = 39.275
Answer:
6
Step-by-step explanation:
First you find a common denominator, which is 12 ( as 4,3 and 6 all go into 12). So 2/4 becomes 6/12, as 4 multiplied by 3 is 12 and whatever you do to the denominator you must do to the numerator. Then 2/3 becomes 8/12. And 2/6 becomes 4/12. If you put these in order the answer is:
2/6, 2/4, 2/3
To solve this problem you must keep on min the information given in the problem shown above:
1- You have that
<span>
- The height reached by amal's rocket was 1/4 of the height reached by min's rocket.
- Amal's rocket REAched a height of 15 meters.
</span>
2. Therefore, let's call "x" to the <span>height reached by min's rocket. Then, you have:
</span>
(1/4)x=15
x/4=15
<span> Which equation could be used to find the height reached by min's rocket?
</span>
The answer is: x/4=15
