All categories

3 years ago

If the statement is true, select True. If it is false, select False.

2 answers:

7 0

The actual relative strengths will vary depending on the molecules involved. Ionic bonding and covalent bonding will always be stronger than intermolecular forces in any given substance.

MAVERICK [17]3 years ago

4 0

The forces between molecules are much stronger than the forces between ions.

➜ True

You might be interested in

Which tiny, round “factory” puts together protein and is often found in the endoplasmic reticulum?

hodyreva [135]

In the cytoplasm, ribsomal RNA (rRNA), a type of RNA, and protein combine to form a nucleoprotein called a ribosome. The ribosome serves as the site and carries the enzymes necessary for protein synthesis. They are often takes the shape of small round particles attached in the endoplasmic reticulum. The ribosome attaches itself to m-RNA and provides the stabilizing structure to hold all substances in position as the protein is synthesized. Several ribosomes may be attached to a single RNA at any time.

8 0

3 years ago

Read 2 more answers

[Cr{P(CH2CH3)3}6]2(SO4)3

gogolik [260]

Don’t understand lol... but I’m chasing those points so thanks

3 0

3 years ago

What does the speed of a sound depend on?

umka2103 [35]

Answer: C. The volume of the sound

Explanation:

6 0

3 years ago

Read 2 more answers

What is 0.570qt to mL

lutik1710 [3]

539.421ml would be the correct conversion

7 0

4 years ago

Positive Deviation from Raoult's Law occurs when the vapour pressure of component is greater than what is expected in Raoult's L

8090 [49]

Answer:

All of the above.

Explanation:

In positive deviation from Raoult's Law occur when the vapour pressure of components is greater than what is expected value in Raoult's law.

When a solution is non ideal then it shows positive or negative deviation.

Let two solutions A and B to form non- ideal solutions.let the vapour pressure of component A is $P_A$ and vapour pressure of component B is $P_B$ .

$P^0_A$ = Vapour pressure of component A in pure form

$P^0_B$ = Vapour pressure of component B in pure form

$x_A$ =Mole fraction of component A

$x_B=$ =Mole fraction of component B

The interaction between A- B is less than the interaction A- A and B-B interaction.Therefore, the escaping tendency of liquid molecules in mixture is greater than the escaping tendency in pure form.Hence, the vapour pressure of a mixture is greater than the initial value of vapour pressure.

$P_A >P^0_A\cdot x_A$ , $P_B>P^0_B\cdot x_B$

Therefore, $P_A+P_B >P^0_A\cdot x_A+P^0_B \cdot x_B$

Therefore, the enthalpy of mixing is greater than zero and change in volume is greater than zero.

Hence, option a,b,c and d are true.

6 0

4 years ago