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nalin [4]
3 years ago
8

Which tiny, round “factory” puts together protein and is often found in the endoplasmic reticulum?

Chemistry
2 answers:
hodyreva [135]3 years ago
8 0
<span>In the cytoplasm, ribsomal RNA (rRNA), a type of RNA, and protein combine to form a nucleoprotein called a ribosome. The ribosome serves as the site and carries the enzymes necessary for protein synthesis. They are often takes the shape of small round particles attached in the endoplasmic reticulum. The ribosome attaches itself to m-RNA and provides the stabilizing structure to hold all substances in position as the protein is synthesized. Several ribosomes may be attached to a single RNA at any time.  <span> </span></span>
Charra [1.4K]3 years ago
4 0
I believe that the answer is B , chloroplast. you can work out the problem any other wat too.

i hope this helps
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Solubility. In each of the following pairs of amino acids, identify which amino acid would be most soluble in water: (a) Ala, Le
Svetllana [295]

Answer:

(a) Ala; (b) Tyr; (c) Ser; (d) His

Explanation:

The general formula for an amino acid is NH₂-CH(R)-COOH

The differences among the different amino acids is caused by the side groups R.

(a) Ala, Leu

Ala: R =                 CH₃-

Leu: R = (CH₃)₂CHCH₂-

Leucine has a larger hydrophobic side group. It should be the less soluble of the pair,

Alanine is the more soluble amino acid.

(b) Tyr, Phe

Tyr: R = HOC₆H₄CH₂-

Phe: R =      C₆H₅CH₂-

Tyrosine has a polar OH group. It can form hydrogen bonds with water.

Tyrosine is the more soluble amino acid.

(c) Ser, Ala

Ser: R = HOCH₂-

Ala: R =       CH₃-

Serine has a polar OH group. It can form hydrogen bonds with water.

Serine is the more soluble amino acid.

(d) Trp, His

Trp: R =       Indole-CH₂-

His: R = Imidazole-CH₂-

Tryptophan has a large aromatic hydrophobic side chain.

Histidine is a basic amino acid. At pH 7 it exists mainly as the anion NH₂CHRCOO⁻, which is hydrophilic.

Histidine is the more soluble amino acid.

4 0
3 years ago
Calculate the quantity of electricity obtained from 2 moles of electrons​
Vinil7 [7]

The quantity of electricity : 2 Faraday = 193000 Coulomb

<h3>Further explanation</h3>

Given

2 moles of electrons

Required

The quantity of electricity

Solution

According to Faraday, the amount of current flowing in the electrolysis cell is closely related to the amount of substance that reacts

1 Faraday is the amount of electricity that is passed in the electrolysis cell to obtain 1 mole of electrons. 1 mole of electrons is equivalent to an electric charge of 96500 Coulombs.

The conversion / relationship can be stated as follows:

1 Faraday = 1 mole of electrons = 96500 Coulombs

1 faraday = coulomb / 96500

Can be formulated

Coulomb = Q = I. t so:

\large {\boxed {\bold {1 \: Faraday \: = \: \dfrac {i \: x \: t} {96500}}}}

so for 2 moles electrons :

= 2 x 96500 C

= 193000 C

= 2 Faraday

6 0
3 years ago
The thermal energy of an object is
kompoz [17]

Answer:

The energy contained in its molecules movement and vibration

Explanation:

See above

3 0
3 years ago
Read 2 more answers
Which mass of magnesium sulphate will be formed if 12 g of magnesium are reacted with sulphuric acid?
Alinara [238K]

Answer:

magnesium hydrosulphate

4 0
3 years ago
A 1.00 liter solution contains 0.43 M hydrofluoric acid and 0.56 M potassium fluoride. If 0.280 moles of potassium hydroxide are
kolbaska11 [484]

Answer:

Answers are in the explanation

Explanation:

Equlibrium of HF in H₂O is:

HF + H₂O ⇄ F⁻ + H₃O⁺

Now, the KOH reacts with HF, thus:

KOH + HF →  F⁻ + H₂O

<em>That means after reaction, concentration of HF decrease increasing F⁻ concentration.</em>

Now, seeing the equilibrium, as moles of HF decrease and F⁻ moles increase, the equilibrium will shift to the left decreasing H₃O⁺ concentration.

For the statements:

A. The number of moles of HF will increase. <em>FALSE</em>. HF react with KOH, thus, moles of HF decrease

B. The number of moles of F- will decrease. <em>FALSE</em>. The reaction produce  F⁻ increasing its moles.

C. The equilibrium concentration of H₃O⁺ will increase. <em>FALSE. </em>The equilibrium shift to the left decreasing concentration of H₃O⁺

D. The pH will decrease. <em>FALSE</em>. As the H₃O⁺ concentration decrease, pH will increase

E. The ratio of [HF] / [F-] will remain the same. <em>FALSE</em>. Because moles of HF are decreasing whereas F- moles are increasing changing, thus, ratio.

6 0
4 years ago
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