Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
13
Step-by-step explanation:
The answer is 400
Have a wonderful day
Answer:14
Step-by-step explanation:
Answer:
Step-by-step explanation:
2.25m + 2(2.25m) + 90 cm =
2.25m + 4.50m + 90 cm
6.75m + 90 cm
1 cm = 0.01m...so 90 cm = 90 * 0.01 = 0.9m
6.75m + 0.9m = 7.65m <===
