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almond37 [142]
3 years ago
7

Which statement can be used to prove that a given parallelogram is a rectangle?

Mathematics
2 answers:
RSB [31]3 years ago
7 0

The <em>correct answer</em> is:


The diagonals of the parallelogram are congruent.


Explanation:


In every parallelogram, opposite angles are congruent. This would not mean it is a rectangle.


Consecutive sides of a parallelogram are only congruent if the parallelogram is a rhombus or a square; this would not be a rectangle.


The diagonals of every parallelogram bisect each other. This would not mean it is a rectangle.


The diagonals of a rectangle bisect each other. If we know this is true about our parallelogram, this means our parallelogram is a rectangle.

Andru [333]3 years ago
3 0
The correct answer of the given question above would be the last option. The statement that can be used to prove that a given parallelogram is a rectangle is the diagonals of the parallelogram are congruent. <span>A </span>rectangle<span> is a parallelogram with four right angles. Hope this answer helps.</span>
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Which of the following equations is equivalent to −6x+2y=24?
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Answer:

The choice three ;

y = 3x + 12

Step-by-step explanation:

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2 years ago
What is the volume of a rectangular solid that is 40 centimeters long, 10 centimeters wide, and 5 centimeters high?
Arturiano [62]

The formula for the volume of a rectangular solid is V = L*W*H

Multiply out the length, width and height given: 40*10*5 = 400*5 = 2000

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3 years ago
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Roman55 [17]

Answer:

Graph A.

Step-by-step explanation:

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2 years ago
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Sage has 3 strip-mats, 3 mats, and 2 units. Tristan has 2 mats, 8 strips, and 5 units. Andre had twice as many strip-mats, mats,
sladkih [1.3K]

The question is an illustration of equivalent equations.

<em>There are 11 units in all</em>

The given parameters are:

<u>Sage</u>

\mathbf{Strip-mat = 3}

\mathbf{Mat = 3}

\mathbf{Units = 2}

<u>Tristan</u>

\mathbf{Strip-mat = 8}

\mathbf{Mat = 2}

\mathbf{Units = 5}

Andre has twice of what Sage has

So, the total unit is:

\mathbf{Total = Sage + Tristan + Andre}

<em>Sage has 2 units</em>

<em>Tristan has 5 units</em>

<em />

Because, Andre has twice of what <em>Sage has,</em>

Andre's number of units would be 4

So, we have:

\mathbf{Total = 2 +5 + 4}

\mathbf{Total = 11}

Hence, there are 11 units in all

Read more about equivalent equations at:

brainly.com/question/18720297

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2 years ago
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rjkz [21]

Answer:

A (?)

Step-by-step explanation:

5 0
3 years ago
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