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2 years ago

What gas will make a flame pop then go out

Chemistry

1 answer:

Vitek1552 [10]2 years ago

8 0

Answer:

Hydrogen Gas

Explanation:

The hydrogen gas now in the test tube is flammable. So when I hold the tube over the flame, the hydrogen gas ignites and creates a popping sound. It is like a tiny bomb or fireworks.

Hope this helped! :)

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An atom of sodium can transfer its one valence electron to an atom of...

diamong [38]

Answer: Either give off or gain electrons to make a total of 8

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2 years ago

Standard reduction potentials are based on which element?

Andreas93 [3]

Answer: option B. Hydrogen

Explanation:

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3 years ago

1. When iron is oxidized, what is reduced?

lys-0071 [83]

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Explanation:

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2 years ago

Read 2 more answers

Determain the number of moles in 2.24l of ch4 at stp

valkas [14]

Answer:

0.1 mole of CH₄

Explanation:

From the question given above, the following data were obtained:

Volume of CH₄ = 2.24 L

Number of mole of CH₄ =?

The number of mole of CH₄ can be obtained as follow:

Recall:

1 mole of a gas occupy 22.4 L at stp. This implies that 1 mole of CH₄ occupies 22.4 L at stp.

22.4 L = 1 mole of CH₄

Therefore,

2.24 L = 2.24 × 1 mole of CH₄ / 22.4

2.24 L = 0.1 mole of CH₄.

6 0

2 years ago

Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a

svetoff [14.1K]

Answer:

The answer to your question is P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

= 373°K

Formula

$(P + \frac{a}{v^{2}} )(v - b) = RT$

Substitution

$(P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)$

Simplify

(P + 0.0094)(22.3829) = 30.586

Solve for P

P + 0.0094 = $\frac{30.586}{22.3829}$

P + 0.0094 = 1.366

P = 1.336 - 0.0094

P = 1.357 atm

7 0

3 years ago