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Naddik [55]
2 years ago
6

How many moles of H₂O can be produced when 5.5 moles of CO₂ is produced? C₂H₄ + 3 O₂ --> 2 CO₂ + 2 H₂O

Chemistry
1 answer:
mrs_skeptik [129]2 years ago
6 0

Answer:

5.5 mol H2O

Explanation:

Given over what you need and then mole ratio of coefficients in the balanced equation then cross multiply and do PEMDAS for that, and then you got your answer :) hope this helped.

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How do you pass sience
MariettaO [177]

Answer:

Listen in Class. The first step to passing any test is to begin preparing right there in the classroom. ...

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Explanation:

8 0
3 years ago
How many milliliters of a 0.215 molar solution are required to contain 0.0867 mol of NaBr
JulsSmile [24]

Answer: 403ml

Explanation:

M=\frac{mol}{L}

Solve for L;

L=\frac{mol}{M}\\L=\frac{0.0867mol}{0.215M}\\ L=0.403L

Convert to mililiters

0.403L(\frac{1000ml}{1L})=403ml

3 0
2 years ago
HELP PLEASE THIS IS CONFUSING
Rasek [7]

Number of moles = 8.3 x 10⁻¹³

<h3>Further explanation </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³  particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's =  6.02.10²³

5 x 10¹¹ atoms of Silver :

\tt mol=\dfrac{5\times 10^{11}}{6.02\times 10^{23}}=8.3\times 10^{-13}

5 0
3 years ago
What is the definition of RNA<br>Messenger RNA<br>and <br>Ribosome?<br><br>​
IceJOKER [234]
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4 0
2 years ago
What is the measured component of the orbital magnetic dipole moment of an electron with (a) ml = and (b) ml = ?
faust18 [17]

ANSWER:

What is the measured component of the orbital magnetic dipole moment of an electron with the values

(a)  ml=3

(b ) ml= −4

a) -278 x 10^{-23}J/T

b) 3.71 x 10^{-23}J/T

STEP-BY-STEP EXPLANATION:

a) ml= 3

Цorb,z = ml Цв = - (3) * (9.27e - 24) = -278 x 10^{-23}J/T

b) ml= 3

Цorb,z = ml Цв = - (-4) * (9.27e - 24) = 3.71 x 10^{-23}J/T

3 0
3 years ago
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