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jarptica [38.1K]
3 years ago
9

What is the slope of the line that includes points (15,-3) and (16,1)

Mathematics
1 answer:
Rasek [7]3 years ago
6 0

Answer:

-4

Step-by-step explanation:

I hope this helps

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Write the linear equation in Slope-Intercept Form y = mx + b of the line that passes through the given points, then graph
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Answer:

y = 3x + 7.

To graph the line mark off the 2 points and draw a line through them.

Step-by-step explanation:

The slope = (-2-7) / (-3-0)

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= 3.

The value of b is found using the point-slope form of a line:

y - y1 = m(x - x1)

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Points (0,6) and (-4,y) lie on the line with a slope of 5
Anna [14]

For this case we have that by definition, the slope of the line is given by:

m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}}

According to the statement we have:

(x_ {1}, y_ {1}) :( 0,6)\\(x_ {2}, y_ {2}): (- 4, y_{2})\\m = 5

Substituting the values:

5 = \frac {y_ {2} -6} {- 4-0}\\5 = \frac {y_ {2} -6} {- 4}\\5 * -4 = y_ {2} -6\\-20 = y_ {2} -6\\-20 + 6 = y_ {2}\\y_ {2} = - 14

Thus, the value of y_ {2} = - 14

Answer:

y_ {2} = - 14

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