We can just use the remainder theorem here.
Plug the value of -2 into each x variable.
(-2)^3 - 1
-9
<h3>The remainder is -9.</h3>
In any given right triangle, the Pythagorean Theorem can be used to show that it is a right triangle.
The Pythagorean Theorem is a^2+b^2=c^2. In a right triangle, a and b would be the shorter legs of the triangle, while c would be the hypotenuse.
So for this problem, you would plug in the numbers in the order that they are listed to see if it is a right triangle.
F would be: 2^2+4^2=7^2. In this case, the sides are not equal.
G would be: 6^2+8^2=10^2. In this case, 100=100. So this is a right triangle.
H would be: 4^2+9^2=12^2. The sides are not equal.
J would be: 5^2+10^2=15^2. The sides are not equal.
Your answer would be G, since the sides are equal. Hope this helps! :)
qq 7
Step-by-step explanation:
you have to take the hole numer and dive it by the % and if get a decimod round down
3/8=.375
.375 move the decimal two times to the right to make it a percent so it would be 37.5%
Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
