Given:
A(3,0)
B(1,-2)
C(3,-5)
D(7,-1)
1) reflect across x=-4
essentially calculate the difference between the x=-4 line and Px and "add" it in the other direction to x=-4
A(-4-(3-(-4)),0)=A(-11,0)
B(-4-(1-(-4)),-2)=B(-9,-2)
C(-4-(3-(-4),-5))=C(11,-5)
D(-4-(7-(-4)),-1)=D(-15,-1)
2) translate (x,y)->(x-6,y+8)
A(-3,8)
B(-5,6)
C(-3,3)
D(1,7)
3) clockwise 90° rotation around (0,0), flip the x&y coordinates and then decide the signs they should have based on the quadrant they should be in
A(0,-3)
B(-2,-1)
C(-5,-3)
D(-1,-7)
D) Dilation at (0,0) with scale 2/3, essentially multiply all coordinates with the scale, the simple case of dilation, because the center point is at the origin (0,0)
A((2/3)*3,(2/3)*0)=A(2,0)
B((2/3)*1,(2/3)*-2)=B(2/3,-4/3)
C((2/3)*3,(2/3)*-5)=C(2,-10/3)
D((2/3)*7,(2/3)*-1)=D(14/3,-2/3)
Answer:
FORMULA USED-
NUMBER OF SUBSETS OF A SET WITH n ELEMENTS= 2^n
Here our set is { onions, garlic, carrots, brocoli, shrimp, mushrooms, zucchini, green pepper}
Different variations available for ordering pasta with tomato sauce= 28 = 256 ( As here n= 8)
Answer:
The probability of Steve agreeing with the company’s claim is 0.50502.
Step-by-step explanation:
Let <em>X</em> denote the number of green candies.
The probability of green candies is, <em>p</em> = 0.20.
Steve buys 30 bags of 30 candies, randomly selects one candy from each, and counts the number of green candies.
So, <em>n</em> = 30 candies are randomly selected.
All the candies are independent of each other.
The random variable <em>X</em> follows a binomial distribution with parameter <em>n</em> = 30 and <em>p</em> = 0.20.
It is provided that if there are 5, 6, or 7 green candies, Steve will conclude that the company’s claim is correct.
Compute the probability of 5, 6 and 7 green candies as follows:
Then the probability of Steve agreeing with the company’s claim is:
P (Accepting the claim) = P (X = 5) + P (X = 6) + P (X = 7)
= 0.17228 + 0.17946 + 0.15328
= 0.50502
Thus, the probability of Steve agreeing with the company’s claim is 0.50502.
Answer:
lower than Amanda: 816 students
Step-by-step explanation:
An equivalent way in which to state this problem is: Find the area under the standard normal curve to the left (below) 940.
Most modern calculators have built in distribution functions.
In this case I entered the single command normalcdf(-1000,940, 850, 100)
and obtained 0.816.
In this particular situation, this means that 0.816(1000 students) scored lower than Amanda: 816 students.
