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Andreas93 [3]
2 years ago
13

PLEASE PLEASE PLEASE HELP I WILL MARK BRAINALIST

Mathematics
1 answer:
Dima020 [189]2 years ago
8 0

Answer

38 punds or 38.46

Step-by-step explanation:

plz make me brainliest i answered question

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HELP I NEED HELP ASAP
mario62 [17]

Answer:A

Step-by-step explanation:

4 0
2 years ago
By October 19th, Gordon had read 35 pages. Starting on October 20th, he decides to read the same number of pages each day until
PilotLPTM [1.2K]
Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.

8 0
2 years ago
What is the simplified form of<br> (4ab)^2
Alex
Use\ (a\cdot b)^n=a^nb^n\\-----------------\\\\(4ab)^2=4^2a^2b^2=\huge\boxed{16a^2b^2}
7 0
3 years ago
On farm there are 200 cows from those 200 cows there are 150 cows that can give milk .in one corral there are 20 cows. How many
LiRa [457]

Here the two samples should be comparable .

The total number of cows in the farm = 200

the total number of cows giving milk = 150

the total number of cows in corral = 20

Suppose total number of cows giving milk in corral = x

The ratio of the total number of cows present to the total number of cows giving milk should be same in farm and corral

so : 200 = 20

------- -------

150 x

now we do cross multiplication :

200 x = 150* 20

200x = 3000

x= 3000/200

x= 15

SO we expect 15 cows in corral should be giving milk .

Answer : 15

4 0
2 years ago
Read 2 more answers
The population of a type of local dragonfly can be found using an infinite geometric series where a1 = 65 and the common ratio i
hram777 [196]
In mathematics, number sequencing of the same pattern are called progression. There are three types of progression: arithmetic, harmonic and geometric. The pattern in arithmetic is called common difference, while the pattern in geometric is called common ratio. Harmonic progression is just the reciprocal of the arithmetic sequence.

The common ratio is denoted as r. For values of r<1, the sum of the infinite series is equal to

S∞ = A₁/(1-r), where A1 is the first term of the sequence. Substituting A₁=65 and r=1/6:

S∞ = A₁/(1-r) = 65/(1-1/6)
S∞ = 78


6 0
3 years ago
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