Answer:
The net in the attached figure
Step-by-step explanation:
we know that
The surface area of the square pyramid using a net, is equal to the area of a square plus the area of its four lateral triangular faces
so
![SA=16^2+4[\frac{1}{2}(16)(13)]](https://tex.z-dn.net/?f=SA%3D16%5E2%2B4%5B%5Cfrac%7B1%7D%7B2%7D%2816%29%2813%29%5D)
Answer:let
Length =L
Width =W
L=5W
Perimeter(p)=2L+2W
P=10W+2W
84=12W
Divide both sides by 12
W=7m
L=5*7=35m
Hence, the length and width are 35m and 7m respectively
Step-by-step explanation:
Answer:
Range of the function → {24, 375}
Step-by-step explanation:
Domain of the function f(x) = 3x³ is {2, 5}
we have to find the range when its domain is {2, 5}
Since x-values of any function define the domain and y-values define the range.
For x = 2,
f(2) = 3(2)³ = 24
For x = 5,
f(5) = 3(5)³ = 375
Therefore, range of the given function for the given domain will be {24, 375}.
Y - 4x = 7...y = 4x + 7
now sub 4x + 7 in for y in the other equation
2y + 4x = 2
2(4x + 7) + 4x = 2
8x + 14 + 4x = 2
12x = 2 - 14
12x = - 12
x = -1
y - 4x = 7
y - 4(-1) = 7
y + 4 = 7
y = 7 - 4
y = 3
solution is : (-1,3)
