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zysi [14]
3 years ago
6

the cost of a small cup of coffee at a deli is $3.50. You can use the equation t=3.5n, where t represents the total money made f

rom the sale of small coffees and n is the number of cups of small coffees sold . In this equation, which describes the role of n?
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0
3.5, it is the coefficient and describes how many n there are
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Given the proportion 3/4 = x/10 , the value of x is:
Drupady [299]

Answer:

7.5

Step-by-step explanation:

given:

3/4 = x/10    (multiply both sides by 10)

(3/4)(10) = x

x = 30/4

x = 7.5

7 0
3 years ago
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The half-life of a certain radioactive material is 78 hours. An initial amount of the material has a mass of 790 kg.. Write an e
adoni [48]
<span> half life i= 78 hours 
 amount after 78 hours is 395 kg: 
395 = 790e^(k*78) 

Dividing by 790 and taking natural log
ln (395/790) = (k*78) 
-0.6931 = 78k 
-0.00888 = k  

lets calculate  how much is left after 18 hours: 
Amount(18)
= 790e^(-0.00888*18) 
Amount = 673.301 kg
hope this helps</span>
4 0
3 years ago
Read 2 more answers
What is question is asking
Pachacha [2.7K]
A) 72/910
b) 278/910
c) 57/910
d1) same as c) = 57/910
d2) 120/910
d3) 101/910
e) No, they DEPENDANT. 
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5 0
4 years ago
A library is having a book sale to raise money. Hard cover books cost $4 each and paperback books cost $2 each. A person spends
Crank
I don't really know how to explain, but I will give you the straight up answer

5 HARDCOVER BOOKS (would total up to $20)
3            paperback books (would total up to $6)
4 0
4 years ago
HOW MANY 7 DIGIT TELEPHONE NUMBERS ARE POSSIBLE IF THE FIRST DIGIT CANNOT BE ZERO AND:
hichkok12 [17]

Using the Fundamental Counting Theorem, the number of possible telephone numbers is given by:

a) 900,000.

b) 78,125.

c) 10,000.

<h3>What is the Fundamental Counting Theorem?</h3>

It is a theorem that states that if there are n things, each with n_1, n_2, \cdots, n_n ways to be done, each thing independent of the other, the number of ways they can be done is:

N = n_1 \times n_2 \times \cdots \times n_n

For item a, a multiple of 100 means that the last two digits are 00, hence the parameters are:

n_1 = 9, n_2 = n_3 = n_4 = n_5 = 10, n_6 = n_7 = 1

Hence the number is:

N = 9 x 10^5 = 900,000.

For item b, odd digits are 1, 3, 5, 7 and 9, hence the parameters are:

n_1 = n_2 = n_3 = n_4 = n_5 = n_6 = n_7 = 5

Hence the number is:

N = 5^7 = 78,125.

For item c, if the first 3 digits are 277, the parameters are:

n_1 = n_2 = n_3 = 1, n_4 = n_5 = n_6 = n_7 = 10

Hence the number is:

N = 10^4 = 10,000.

More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866

#SPJ1

3 0
2 years ago
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