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Sedbober [7]
3 years ago
15

Near the end of a marathon race, the first two runners are separated by a distance of

Physics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

a) 4.75-3.25 = 1.50 m/s

b) Time taken to overtake = 65/1.5 = 43.33 seconds

first runner will finish the race in 215/3.25 = 66.15 seconds

So second runner will win the race

ANSWER

c) 65 +215 = 280m

280 / 4.75 = 58.95 seconds

first runner will complete 58.95 X 3.25 = 191.5875 m

So 215-191.5875=23.4125 meters ahead

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A mobile starts with a speed of 250m / s and begins to decelerate at a rate of 3m / s². How fast is it after 45s?
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\large{ \underline{ \underline{ \bf{ \purple{Given}}}}}

  • Speed of the mobile = 250 m/s
  • It starts decelerating at a rate of 3 m/s²
  • Time travelled = 45s

\large{ \underline{ \underline{ \bf{ \green{To \: find}}}}}

  • Velocity of mobile after 45 seconds

\large{ \underline{ \underline{ \red{ \bf{Now, \: What \: to \: do?}}}}}

We can solve the above question using the three equations of motion which are:-

  • v = u + at
  • s = ut + 1/2 at²
  • v² = u² + 2as

So, Here a is acceleration of the body, u is the initial velocity, v is the final velocity, t is the time taken and s is the displacement of the body.

\large{ \bf{ \underline{ \underline{ \orange{Solution:}}}}}

We are provided with,

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  • a = -3 m/s²
  • t = 45 s

By using 1st equation of motion,

⇛ v = u + at

⇛ v = 250 + (-3)45

⇛ v = 250 - 135 m/s

⇛ v = 115 m/s

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