Answer:
13.7m
Explanation:
Since there's no external force acting on the astronaut or the satellite, the momentum must be conserved before and after the push. Since both are at rest before, momentum is 0.
After the push

Where
is the mass of the astronaut,
is the mass of the satellite,
is the speed of the satellite. We can calculate the speed
of the astronaut:

So the astronaut has a opposite direction with the satellite motion, which is further away from the shuttle. Since it takes 7.5 s for the astronaut to make contact with the shuttle, the distance would be
d = vt = 1.83 * 7.5 = 13.7 m
As you said p=w/t.
but, w=f×s
=500×5=2500j
t=10s
p=w/t
=2500/10=250 watts
Explanation:
a. Mechanical advantage = force out / force in
MA = 830 / 100
MA = 8.3
b. Efficiency = work out / work in
0.80 = W / 600 J
W = 480 J
Answer:

Explanation:
Given:
- mass of the honey drop 1,

- velocity of the honey drop 1,

- mass of the honey drop 2,

- velocity of the honey drop 2,

- mass of the honey drop 3,

- velocity of the honey drop 3,

<em>In ISS there is zero gravity an the collision is completely inelastic.</em>
<u>So, applying the law of conservation of momentum:</u>



Answer:
x-component of velocity = 5.7 m/s
y-component of velocity = -1.4 m/s
Explanation:
Use first equation of motion to find components of velocity at a given time:

where,
is the final velocity,
is the initial velocity,
is the acceleration and
is the time.
Given:


