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Sedbober [7]
3 years ago
15

Near the end of a marathon race, the first two runners are separated by a distance of

Physics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

a) 4.75-3.25 = 1.50 m/s

b) Time taken to overtake = 65/1.5 = 43.33 seconds

first runner will finish the race in 215/3.25 = 66.15 seconds

So second runner will win the race

ANSWER

c) 65 +215 = 280m

280 / 4.75 = 58.95 seconds

first runner will complete 58.95 X 3.25 = 191.5875 m

So 215-191.5875=23.4125 meters ahead

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Why are most of the world’s deserts located between latitudes 10°n to 30°n and 10°s to 30°s.
RoseWind [281]

The bulk of the world's deserts are located at 30 degrees north latitude and 30 degrees south latitude, when the warm equatorial air begins to descend. The heavy, warm, descending air vaporises large amounts of water from the ground's surface. As a result, the environment is rather dry.

<h3>Why are the majority of the desert regions on Earth located between 20 and 30 degrees latitude?</h3>

The zones of falling air are those between 20 and 30 latitudes on the western borders of continents (high pressure and dry weather). As a result, the moisture continues to decrease as the air is compressed and warmed as it falls.

Where the scorching equatorial air starts to descend, the majority of the world's deserts are found between 30 degrees north and 30 degrees south latitude. Large volumes of water are vaporised off the surface of the ground by the thick, warming, falling air. As a result, the climate is extremely dry.

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3 0
1 year ago
As a car moves along the road, the distance traveled each second is measured and recorded. What is the
scoundrel [369]
If the car moves along the distance it will be 16 of the line graph where is independent of the graph
8 0
3 years ago
The switch has been open for a long time before it is closed at t = 0. what is ustored, the total stored energy in the circuit e
Ivahew [28]
0. No time comparison.
5 0
3 years ago
g A motorist traveling at 30.0 m/s passes a stationary police car. The police car gives chase 2.0 s later, accelerating at 5.0 m
Sedaia [141]

The time for the police car to catch up with the speeding motorist is 7.6 seconds.

<h3>What time will the police car catch up with the speeding motorist?</h3>

The police car and the motorist will cover equal distances.

Let the distance covered be d.

Distance covered by the motorist  = speed * time

time = t, speed = 30 m/s

d = 30t

Distance covered by the police car = acceleration * (time)

time = t - 2, acceleration = 5.0 m/s²

d = 5(t-2)²

d = 5(t² - 4t + 4)

d = 5t² - 20t + 20

Equating the two equations for distance

5t² - 20t + 20 = 30t

5t² - 50t + 20 = 0

Solving for t using the quadratic formula:

t = 9.6 second or 0.4 seconds

Since t > 2, t = 9.6 seconds

t - 2 = 9.6 - 2

t - 2 = 7.6 seconds

Therefore, the time for the police car to catch up with the speeding motorist is 7.6 seconds.

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4 0
1 year ago
Explain why radio and television stations use different frequencies to broadcast programs.
Sedaia [141]

I'm not sure exactly what you're asking.

It could be


==> Why do radio stations use different frequencies from TV stations ?


or it could be


==> Why don't all radio stations, or all TV stations, use the same frequency ?


Radio and TV can't coexist among each other in the same "band"

of frequencies, because they use different amounts of "space" on

the dial. One analog TV channel uses enough dial space for about

600 AM radio stations, or 30 FM radio stations ! That's one click on

the TV channel knob !

So if they were all jumbled up together on the same dial and you

wanted to tune your radio from one AM station to another, you

might have to crank through enough space for 600 radio stations ...

or even 1200 or 1800 of them ... to go to the AM signal you want.

And maybe even worse than that ! I'm sure you've never heard what

a TV signal SOUNDS like on a radio. It is horrendous, and it is loud !

It sounds like a thousand cats shrieking at each other, and it never stops.

That's another good reason to move the TV transmissions to frequencies

where radios will never hear them. If radios just randomly tuned in to a

TV picture signal every now and then, a lot of people would be shocked

out of their socks. They would stop listening to radio, and thousands of

advertisers would not like that.


For the second question ...

OK, so we don't mix radio and TV in the same band of frequencies.

But why does each station need its own frequency ? Why not just

put every radio station on one frequency, and every TV station on

a single frequency that's different from the radio frequency ?

The answer is: It's because people don't want to listen to two radio

stations at the same time, or watch two TV movies at the same time.

We like to make our choice, and then watch them or listen to them

one at a time. And FREQUENCY is the only way our radios and TVs

know how to pick out ONE and ignore all the others.

If there are two, or 5 or 10 stations all on the same frequency within

10 or 20 miles from you, then when you tune your radio to that frequency,

you HEAR two, or 5 or 10, songs, church services, newscasts, political

speeches, or commercials, all at the same time.

So if all radio stations were on the same frequency, or all TV stations

were all on the same frequency, then any time you turned on your

radio or TV, you'd see or hear all of them together. Radio and TV

would completely lose their entertainment value, everybody would

give up watching and listening, and once again ... thousands of

advertisers would not like that.


After all, advertising is the main reason why we have so much radio and TV at all. The advertiser buys, the broadcaster sells, and YOUR eyes and ears are the product.
5 0
3 years ago
Read 2 more answers
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