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Leviafan [203]
3 years ago
15

What is the main difference between velocity and speed?

Physics
1 answer:
Marina86 [1]3 years ago
4 0
Speed is scalar, meaning it's only going to be like 74 mph, doesn't matter which direction. Velocity is a vector, meaning it has direction. You can go -74mph when talking about velocity, not speed.
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Assume that the stopping distance of a van varies directly with the square of the speed. A van traveling 40 miles per hour can s
Daniel [21]

Answer:

d = 100.8 ft

Explanation:

As we know that initial speed of the van is 40 miles then the stopping distance is given as 70 feet

here we know that

v_f^2 - v_i^2 = 2 ad

so here we have

0^2 - 40^2 = 2 a (70 feet)

now again if the speed is increased to 48 mph then let say the stopping distance is "d"

so we will have

0^2 - 48^2 = 2 a (d)

now divide the above two equations

\frac{40^2}{48^2} = \frac{70 feet}{d}

d = 100.8 ft

4 0
3 years ago
A force of 30.0 N is applied to a 3.00 kg object for 3.00 seconds. Calculate the velocity experienced by the object.
olganol [36]

Answer:

Explanation:

F = ma and

a=\frac{v}{t}

We have F, we have m, but in order to solve for v, we need a.

30.0 = 3.00a so

a = 10.0 m/s/s. Plug that in for a in the second equation and solve for v:

10.0=\frac{v}{3.00} so

v = 10.0(3.00) so

v = 30.0 m/s

6 0
2 years ago
If a vector that is 3cm long represents 30 km/h, what velocity does a 5 cm long vector which is drawn using the same scale repre
FrozenT [24]

Answer:

False knowww yess ofcure

8 0
3 years ago
You lift a large bag of flour from the floor to a 2.5m high counter, doing 400J of work in 2 seconds. How much force did you app
oksian1 [2.3K]
<h2>The man have to apply force of 160 N</h2>

Explanation:

The work done to lift the bag of weight mg through height 2.5 m is 400 J

The work done can be found by relation  W = mg x h

Thus mg = \frac{W}{h} = \frac{400}{2.5} =  160 N

Therefore the man have to apply the force of 160 N

7 0
3 years ago
Read 2 more answers
Encuentra la masa molar<br><br> TO<br><br> de 65 litros de SO2
shepuryov [24]

La masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

<h3>Masa molar</h3>

La masa molar de un compuesto depende de su masa presente en 1 mol, entonces:

                                          MM=\frac{m}{mol}

Para calcular la masa molar de un compuesto, simplemente suma las masas de cada elemento en el compuesto, así:

MM_O = 16g/mol\\MM_S= 32.1g/mol

                                32.1 + 2\times 16 = 64.1g/mol

Así, la masa molar de 65 litros de SO2 es igual a 64,1 g/mol.

Obtenga más información sobre la masa molar en: brainly.com/question/17109809

8 0
2 years ago
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