Answer:
Is that your answer ☺️☺️☺️
If the velocity is constant then the acceleration of the object is zero.

Thus when we apply the equation

It remains

or equivalent
Answer:
F = 4856.32 N
Explanation:
Given,
A satellite is orbiting earth at a distance from Earth surface, h = 35000 m
The mass of the satellite, m = 500 Kg
The radius of the Earth, R = 6.371 x 10⁶ m
The mass of the Earth, M = 5.972 x 10²⁴ Kg
The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²
The force between the Earth and the satellite is given by the formula
F = GMm/(R+h)² N
Substituting the values in the above equation
F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²
= 4856.32 N
Hence, the force between the planet and the satellite is, F = 4856.32 N
We know that
tan(∅) = y/x; where y will be the height of the balloon and x will be the distance from the milestone marker.
The marker that is further away will produce a smaller angle of depression.
tan(18) = height / x
x = height / tan(18)
The second marker is x + 1 miles away:
tan(16) = height / x + 1; substituting x:
tan(16) = height / (height/tan(18) + 1)
tan(16) x [(height / tan(18) + 1] = height
0.88h + 0.29 = h
h = 2.42 miles