Answer:

Explanation:
From the question we are told that
Two points charge of 4\mu C and 2\mu C
Generally we find the Va and Vb individually to find there difference
Given a rectangle with two equal sides each,Assume lengths for bot sides
Length L=0.3
Breath B=0.4
Diagonal D=
at opposite sides
Mathematically Va can represented as





Mathematically Vb is represented as





Therefore

You need distance and time to find average speed.
Answer:
true is the answer of the question
The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
<h3>What is the magnitude of electrical forces between two charges?</h3>
The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.
The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.
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Answer:
θ₂ = 35.26°
Explanation:
given,
refractive index of air, n₁ = 1
refractive index of glass, n₂ = 1.5
angle of incidence, θ₁ = 60°
angle of refracted light, θ₂ = ?
using Snell's Law
n₁ sin θ₁ = n₂ sin θ₂
1 x sin 60° = 1.5 sin θ₂
sin θ₂ = 0.577
θ₂ = sin⁻¹(0.577)
θ₂ = 35.26°
Hence, the refracted light is equal to θ₂ = 35.26°