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myrzilka [38]
3 years ago
13

PLEASE HELP it’s due in 30 minutes

Chemistry
1 answer:
Nady [450]3 years ago
6 0

Answer:

1-6

3 1 3 3 2 2

Explanation:

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The reaction between iron(II) oxide and carbon monoxide produces iron and carbon dioxide. How many moles of iron can be obtained
My name is Ann [436]

Answer:

4.75 moles of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

FeO + CO —> Fe + CO2

Now, we can determine the number of mole of iron, Fe produced by the reaction of 4.75 mol of FeO with excess CO as follow:

From the balanced equation above,

1 mole of FeO reacted to produce 1 mole of Fe.

Therefore, 4.75 moles of FeO will also react to produce 4.75 moles of Fe.

Therefore, 4.75 moles of Fe is produced.

4 0
3 years ago
Is sugar a compound or a mixture?
puteri [66]

Answer:

compound

Explanation:

3 0
2 years ago
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What is responsible for the difference in climate between eastern and western California
PilotLPTM [1.2K]
I believe that the answer is D. 

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7 0
3 years ago
What is the freezing point of an aqueous 1.58 molal nacl solution?
Alina [70]
<span>Tf is the freezing point of the solution(the solvent plus solute). T*f is the freezing point of the pure solvent(without solute) i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1. Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol. Tf is -1.58 Degree C</span>
4 0
3 years ago
How many formula units make up 36.0 g of magnesium chloride (MgCl2)?
zalisa [80]

Answer: There are 2.29\times 10^{23} formula units

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{36.0g}{95g/mol}=0.38moles

1 mole of MgCl_2 contains = 6.023\times 10^{23} formula units

Thus 0.38 moles of MgCl_2 contains = \frac{6.023\times 10^{23}}{1}\times 0.38=2.29\times 10^{23} formula units

Thus there are 2.29\times 10^{23} formula units

6 0
3 years ago
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