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Alexus [3.1K]
2 years ago
10

Is this a function?

Mathematics
1 answer:
Anna [14]2 years ago
7 0
If their is supposed to be a picture I don’t see one
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A research scientist wants to know how many times per hour a certain strand of bacteria reproduces. He wants to construct the 95
Galina-37 [17]

Answer:

The minimum sample size required for the estimate is 345.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

The standard deviation is known to be 1.8.

This means that \sigma = 1.8

What is the minimum sample size required for the estimate?

This is n for which M = 0.19. So

M = z\frac{\sigma}{\sqrt{n}}

0.19 = 1.96\frac{1.8}{\sqrt{n}}

0.19\sqrt{n} = 1.96*1.8

\sqrt{n} = \frac{1.96*1.8}{0.19}

(\sqrt{n})^2 = (\frac{1.96*1.8}{0.19})^2

n = 344.8

Rounding up to the next integer:

The minimum sample size required for the estimate is 345.

8 0
3 years ago
Ten runners join a race. In how many possible ways can they be arranged as first, second, and third placer? Pls answer
Daniel [21]
Ans: 720

<span>This is equal to the number of different arrangements of three persons from a group of 10 persons </span>

Required number of ways = 10P3 = 720

OR can be solved in this way
select 3 runners (10C3 ways)
These 3 runners can be arranged in 3! ways
<span>Total = 10C3×3! = 720

</span>
5 0
3 years ago
Read 2 more answers
In ΔQRS, q = 890 cm, s = 810 cm and ∠S=120°. Find all possible values of ∠Q, to the nearest degree.
Lelechka [254]

Answer: no possible triangles

Step-by-step explanation:

4 0
3 years ago
I need help with this, please answer right I will give brainelist
Gekata [30.6K]

Answer:

1 D. 400 spins

2 C.4/20

3 A. 6/20

Step-by-step explanation:

1

The more times you run a probability-based trial, the more likely you are to get close to the theoretical frequency.

2

Since 1 and 2 represent goals, just find the options that have three/four 2's and 1's. These are 5212, 2152, 2512, and 2112. Since there are 4 options out of 20, we can say our probability is 4/20

C

Since 1 and 2 represent goals, we have to find the options where there are no 1's or 2's. These are 6643, 3554, 4533, 6634, 4536, and 5546. Since there are 6 options out of 20, we can say our probability is 6/20

8 0
3 years ago
A family purchased tickets to a museum and spent a total of $38.00. The family purchased 4 tickets. There was a $1.50 purchasing
Naya [18.7K]

Answer:

4 (x+1.50) = $38.00

Explanation:

The family purchases 4 tickets. Each tickets cost x dollars with a purchase fee of $1.50. So we need to multiply 4 times the sum of x plus $1.50. The total cost of the tickets needs to be $38.00.

8 0
3 years ago
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