${(\sin(a)+ \cos(b)})^{2} = \\{\sin(a)}^{2} + 2\sin(a)\cos(b)\\ + {\cos(b)}^{2} \\ {(\sin(a) - \cos(b)})^{2} = \\{\sin(a)}^{2} - 2\sin(a)\cos(b) + {\cos(b)}^{2}$

$2\sin(a)\cos(b) cancel :\ out\\$

$=2{\sin}^{2}(a) +2{\cos}^{2}(a)$

3 0

3 years ago

A jewellery store sells 240 necklaces in a month. 180 of the necklaces were sold via the shop’s website, the rest were sold in a

Gnom [1K]

3 in store to 4 online

3 0

3 years ago

Read 2 more answers

The width, y, of a rectangle with a fixed area varies inversely with its length, x. The width is 3 inches when the length is 14

IrinaVladis [17]

Answer:

$y = 1.4$

Step-by-step explanation:

Given

$y = width$

$x = length$

$y = 3;\ when\ x = 14$

Required

Find y when x = 30

Being an inverse variation, we have:

$y\ \alpha\ \frac{1}{x}$

Convert the variation to an equation

$y = \frac{k}{x}$

First, we solve for k

Make k the subject to solve for k

$k = xy$

$y = 3;\ when\ x = 14$

So, the value of k is:

$k = 14 * 3$

$k = 42$

To solve for y when x = 30

Substitute 30 for x and 42 for k in $k = xy$

$42 = 30 * y$

Make y the subject

$y = \frac{42}{30}$

$y = 1.4$

6 0

3 years ago

Someone hurry and help plsss

Damm [24]

Answer:

-3 is the answer for the question

5 0

3 years ago