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Anna71 [15]
3 years ago
6

3. A cart (m= 10.0 kg) is currently traveling with a velocity of 3.0 m/s. The cart then gains speed,

Physics
1 answer:
KiRa [710]3 years ago
6 0

First we calculate the acceleration of the cart:

a = (v₂ - v₁) / (t)

a = (7 m/s - 3 m/s) / (8 s)

a = 4 m/s / 8 s

a = 0.5 m/s²

Using the Newtons Second Law:

F = m×a

F = (10 kg)(0.5 m/s²)

F = 5 N

<h2>The correct option is C</h2>
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In component form, the displacement vectors become

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• 550 m [N 10° W]   ==>   (550 cos(100°), 550 sin(100°)) m

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(0 + 400 cos(20°) + 550 cos(100°), -350 + 400 sin(20°) + 550 sin(100°)) m

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ω = 0.05 rad/s

Explanation:

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Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\

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\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\

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