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aalyn [17]
3 years ago
15

An object with a charge of 0.9 x 10^-5 C is separated from a second object with a chare of 2.5 x 10^-4 C by a distance of 0.5 m.

Calculate the force acting between the charges.
Physics
1 answer:
meriva3 years ago
4 0

Answer: Force = 81 N

Explanation:

from Columbs law,

F = k(q1*q2)/r²

k = 9 x 10^9 Nm²/C²

F = (9 x 10^9)x (0.9x10^-5 x 2.5x10^-4)/(0.5)²

F = 81 Newtons

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Suppose that in a lightning flash the potential difference between a cloud and the ground is 1.0*109 V and the quantity of charg
nata0808 [166]

Answer:

a) U_{e} = 3 \times 10^{10}\,J, b) v \approx 7745.967\,\frac{m}{s}

Explanation:

a) The potential energy is:

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U_{e} = (30\,C)\cdot (1.0\times 10^{9}\,V)

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b) Maximum final speed:

U_{e} = \frac{1}{2}\cdot m \cdot v^{2}\\v = \sqrt{\frac{2\cdot U_{e}}{m} }

The final speed is:

v=\sqrt{\frac{2\cdot (3 \times 10^{10}\,J)}{1000\,kg} }

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3 0
3 years ago
Sallys physical education teacher timed her run and recorded the time and distance in the table below. What is her average speed
Fudgin [204]
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1 + 2 + 3 + 4 + 5 = 15
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7.2 divided by 3 = 2.4

Therefore, the answer is technically 2.4m/s
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4 years ago
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