Answer:
the loss of energy due to the Joule effect is the cause of the non-ohmic characteristic of the bulb
Explanation:
A resistance is formed of some type of metal, in a light bulb it is Tungsten, which for low current is a resistance that complies with the ohm law.
When the value of the current is increased the shock of the electors creates a Joule effect, which heats the metal, these shocks are due to atomic imperfections of the structure, this heating creates a loss of energy of the system that causes the characteristic to be lost linear between the voltage and the current, since the total energy balance must be preserved.
An approximate measure of the energy that is emitted is given by Stefan's law.
In short, the loss of energy due to the Joule effect is the cause of the non-ohmic characteristic of the bulb
Answer:
1. G.P.E = 24 J
2. center of mass
Explanation:
Given the following data;
Mass = 2kg
Height, h = 1.2m
Acceleration due to gravity = 9.8 N/kg or m/s².
To find the gravitational potential energy;
Gravitational potential energy (GPE) is an energy possessed by an object or body due to its position above the earth.
Mathematically, gravitational potential energy is given by the formula;

Where;
- G.P.E represents potential energy measured in Joules.
- m represents the mass of an object.
- g represents acceleration due to gravity measured in meters per seconds square.
- h represents the height measured in meters.
Substituting into the formula, we have;

G.P.E = 23.52 to 2 S.F = 24 Joules.
Translation kinetic energy is defined as the energy of a system due to the motion of the system’s center of mass. The center of mass is typically where the mass of the object or particle is concentrated.
Answer:
1.2 A
Explanation:
From the diagram attached, The three resistors are parallel because the each ends of the resistors are connected together. Since they are in parallel, the voltage across each resistor is the same. The voltage source connected in parallel to the resistors is 60 V. Therefore the voltage across the 50 Ω resistor is 60 V. Using ohm law:
Voltage (V) = Current (I) × Resistance (R)
V = IR
I = V/R
I = 60 V/ 50 Ω
I = 1.2 A
The current in the 50 Ω resistor is 1.2 A
The spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is

Which means that the frequency is

and the angular frequency is

In a spring-mass system, the maximum velocity of the object is given by

where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is