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3 years ago

1) At a diner, the cost for a specialty waffle and a hashbrown is $9.50. The cost for 2 specialty

Mathematics

1 answer:

klemol [59]3 years ago

4 0

9514 1404 393

Answer:

waffle $8
hashbrowns $1.50

Step-by-step explanation:

Using w and h for the costs of a waffle and hashbrowns, respectively, we can write the equations for the purchase amounts as ...

w + h = 9.50

2w + 3h = 20.50

Subtracting twice the first equation from the second gives ...

(2w +3h) -2(w +h) = (20.50) -2(9.50)

h = 1.50 . . . . . . simplify

w = 9.50 -h = 8.00 . . . . . find w using the first equation

The cost of a waffle is $8.00; the cost of hashbrowns is $1.50.

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2 years ago

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Step-by-step explanation:

Given

Equations are $3x-y=23$ and $2x+3y=8$

take $3x-y=23$

$y=3x-23$

Put the value of y in another equation

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3 years ago

The average amount of water in randomly selected 16-ounce bottles of water is 16.15 ounces with a standard deviation of 0.45 oun

vekshin1

Answer:

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 16.15, \sigma = 0.45, n = 35, s = \frac{0.45}{\sqrt{35}} = 0.0761$

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This is the pvalue of Z when X = 15.99. So

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By the Central Limit Theorem

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3 years ago

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Answer:

Step-by-step explanation:

The formula for determining the the area of a sector is expressed as

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