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3 years ago

-0.8 + 40 - 8x - 35 can you please help with this pre algebra

Mathematics

2 answers:

AVprozaik [17]3 years ago

3 0

-8x + 4.2 is the answer

nadezda [96]3 years ago

3 0

Answer:4.2-8x

Step-by-step explanation:

-0.8-40-35=4.2 -8x

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Video games sold: x

Nata [24]

Answer:

The correct answer is D. 53x - 12

Step-by-step explanation:

Let's find P(x), this way:

Profits = Revenue - Cost

Profit function = Revenue function - Cost function

P (x) = R (x) - C (x)

Replacing with the real values we have:

P (x) = 60x - (12 + 7x)

P (x) = 60x - 12 - 7x

P (x) = 53x - 12

The correct answer is D. 53x - 12

6 0

3 years ago

Learning Task 3

ASHA 777 [7]

Answer:

1. The sides are: 38.5, 39.5, 40.5 and 41.5

2. Presently, Inzo is 15 years old and Miz is 10 years old

3. $Distance = 3682km$

4. Possible pairs are: (12, 14), (16, 18) and (20, 24)

5. $L < 38m$

Step-by-step explanation:

The question has lots of missing details. See the comment section for complete question

Solving (a):

Given

Shape: Quadrilateral

Sides: Consecutive

$Perimeter = 160$

Let one of the sides be x. The other sides will be x + 1, x + 2 and x + 3.

So, the perimeter is:

$Perimeter = x + x + 1 + x + 2 + x + 3$

This gives:

$160 = x + x + 1 + x + 2 + x + 3$

Collect Like Terms

$160 -1-2-3= x+x+x+x$

$154= 4x$

Divide both sides by 4

$38.5 = x$

$x =38.5$

So, the sides are: 38.5, 39.5, 40.5 and 41.5

Solving (b):

Given

Presently: $Inzo = 10 + Miz$

Five years ago: $Miz - 5= \frac{1}{3} * (Inzo-5)$ --- (Missing from the question)

Required: Determine their present ages

Substitute $10 + Miz$ for Inzo in the second equation

$Miz - 5 = \frac{1}{3} * (10 + Miz - 5)$

$Miz - 5 = \frac{1}{3} * (Miz + 5)$

Multiply both sides by 3

$3Miz - 15 = Miz + 5$

Collect Like Terms

$3Miz -Miz = 15 + 5$

$2Miz= 20$

Divide both sides by 2

$Miz = 10$

Substitute 10 for Miz in $Inzo = 10 + Miz$

$Inzo = 10 + 5$

$Inzo = 15$

So presently, Inzo is 15 years old and Miz is 10 years old

Solving (3):

Given

Express Train:

$Speed = 100kph$

$Time = t$

Local Train:

$Speed = 45kph$

$Time = t + 45$

Required: Determine the distance between A and B

Distance is calculated as:

$Distance = Speed * Time$

For the express train:

$Distance = 100 * t$

For the local train

$Distance = 45 * (45 + t)$

Distance between both stations are equal; So,

$100 * t = 45 * (45 + t)$

$100 t = 2025 + 45t$

Collect Like Terms

$100 t -45t= 2025$

$55t= 2025$

Divide by 55

$t = 36.82$

Substitute 36.82 for t in $Distance = 100 * t$

$Distance = 100 * 36.82$

$Distance = 3682km$

Solving (4):

Let the even numbers be: n and n + 2.

Sum greater than 24: $n + n + 2 > 24$

Sum less than 60: $n + n + 2 < 60$

So, we have:

$n + n + 2 > 24$

$2n + 2 > 24$

Collect Like Terms

$2n > 24-2$

$2n > 22$

$n > 11$

$n + n + 2 < 60$

$2n + 2< 60$

Collect Like Terms

$2n < 60-2$

$2n < 58$

Divide by 2

$n$

So, we have:

$n > 11$ and $n < 29$

So, possible pairs are: (12, 14), (16, 18) and (20, 24)

Solving (5):

Given

$Perimeter < 152m$

Required: Find the possible lengths

Let the length be L.

Perimeter is calculated as:

$Perimeter =4 * L$

$Perimeter =4 L$

So, we have:

$4L < 152m$

Divide through by 4

$L < 38m$

Hence, length is less than 38m (e.g. 37m)

5 0

2 years ago

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

STatiana [176]

C. Both options A and B will allow him to meet his goal.

Looking at Drake's situation after 4 weeks, he only has $470 saved. By his original plan, he should have had $500 saved. So he's $30 short of his goal and has 2 weeks until his originally planned class. If he goes with option A and takes the later class, he will save an additional $125 which is more than enough to make up the $30 short fall. So option A will work for him to save enough money for his class. With option B, he will save $140 for the last 2 weeks of his plan giving him a savings of $280 for the last 2 weeks. Adding the $470 he's already saved will give him a total savings of $470 + $280 = $750 which is enough for him to attend his class. So option B will also allow Drake to attend his desired class. Both options A and B allow him to meet his goal. Hence, the answer is "c".

8 0

3 years ago

A group of three friends order a combo meal which includes two slices of pizza and a drink. Each drink is priced at $2.50. If th

Fittoniya [83]

Answer:

Step-by-step explanation:

2.5(3)

31.5-(2.5*3)

31.5-7.5

24/3=8

$8 per slice

6 0

3 years ago

what is the explicit formula and recursive formula of the numbers 4,7,10,13,16...i don't even know how to start this problem. i

Lana71 [14]

An arithmetic sequence is a sequence with a constant

increase or decrease also known as the constant difference

In the sequence 10, 40, 70, 100, ….

The constant difference between the terms is 30

A recursive formula for a sequence would be:

a1= first term in the sequence

an = term you are trying to find

an-1 = previous term in the sequence

d = constant difference

Explicit Formulas:

A formula that allows you to find the nth term of the sequence by substituting known values in the expression.

Formula : an = a1 + d( n - 1)

a1= first term in the sequence

an = current term in the sequence

d = constant difference

n = term number

Solution:

Write the explicit formula of the sequence 4, 7, 10, 13, 16 ….

Formula for explicit term:

an = ___ + ___( n - 1)

Simplify: an = ___ + ___n

In the sequence 4, 7, 10, 13, ….

To find the 11th term explicitly, I plug in the into the formula I just made:

an = 1 + 3n

a11 = 1 + 3(11)

a11 = 34

Find the 15th term of the sequence using the formula: an = 1 + 3n

Write the recursive formula of the sequence 4, 7, 10, 13, ….

Recursive formula:

a1 =

an = a n - 1

In the sequence 4, 7, 10, 13, 16 ….

To find the 5th term recursively, I plug it into the formula I just made:

an = an-1 + 3

a5 = a5-1 + 3 in words: 5th term equals the 4th term plus 3

a5 = 13 + 3

a5 = 16

Recursive and Explicit Formulas for Arithmetic (Linear) Sequences

8 0

3 years ago