The value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).
Aa we know that, 125mL of 0.06M Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl.
Given, T = 25°C.
<h3>Chemical equation:</h3>
Pb(NO3)2 + NaCl ---- NaNO3 + PbCl2
PbCl2 in aqueous solution split into following ions
PbCl2 ------ Pb(+2) + 2Cl-
Q = [Pb(+2)] [Cl-]^2
The Concentration of Pb(+2) ions and Cl- ions can be calculated as
[Pb(+2)] = 0.06 × 125/200
= 0.0375
[Cl-] = 0.02 × 75/200
= 0.0075
By substituting all the values, we get
[0.0375] [0.0075]^2
= 2.11 × 10^(-6).
Thus, we calculated that the value of Q for 125.0 ml of 0.0500 m Pb(NO3)2 is mixed with 75.0 ml of 0.0200 m NaCl at 25°C is 2.11 × 10^(-6).
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This element would have 122 neutrons.
Atomic mass is the accumulation of neutrons and protons.
169 - 47 = 122.
Therefore, there are 122 neutrons.
Answer:
air rises most quikly above water so i'm confuse it's lake or river
The tool that can be used is a seismograph.
Answer:
The answer to your question is 0.54M
Explanation:
Data
Final concentration = ?
Concentration 1 = 0.850 M
Volume 1 = 249 ml = 0.249 l
Concentration 2 = 0.420 M
Volume 2 = 0.667 M
Process
1.- Calculate the number of moles in both solutions
Number of moles 1 = Molarity 1 x Volume 1
= 0.850 x 0.249
= 0.212
Number of moles 2 = Molarity 2 x Volume 2
= 0.420 x 0.667
= 0.280
Total number of moles = 0.212 + 0.280
= 0.492
2.-Calculate the final volume
Final volume = Volume 1 + Volume 2
Final volume = 0.249 + 0.667
= 0.916 l
3.- Calculate Molarity
Molarity = 0.492 / 0.916
Molarity = 0.54
