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3 years ago

9

Please help me eeeeeeeeeeeeeeeeeeeeeeeeeeee

1 answer:

erastovalidia [21]3 years ago

8 0

May pagpipilian? hahaha

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Karen runs 6 miles in 55 minutes. At the same rate, how many miles would she run in 44 minutes?

Anna007 [38]

Answer:

x = 4.363636...

Step-by-step explanation:

Set up a ratio

6 miles : 55 minutes

x miles : 40 minutes

Cross Multiply

55x = 40*6

55x = 240

55x / 55 = 240 / 55

x = 4.363636...

8 0

3 years ago

The area of the rectangle shown is 44 m2.<br> | 3 m<br> x m<br> Work out the missing length x.

andrew11 [14]

Answer:

$area = length \times width \\ 44 = 3 \times x \\ x = \frac{44}{3}$

8 0

2 years ago

Which is an equation of the line that passes through the point

Allisa [31]

Answer:

y = $\frac{1}{2} x$ +3

Step-by-step explanation:

4 0

2 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago

Is 3/5 and 6/8 proportional

balandron [24]

3/5 and 6/8 are not proportional as even though 3 goes into 6 evenly, 5 does not go into 8 evenly so that makes it disproportional.

3 0

3 years ago

Read 2 more answers