Answer:
13.78 mT
Explanation:
The peak voltage ε = ωNAB where ω = angular speed of coil = 1500 rpm = 1500 × 2π/60 rad/s = 50π rad/s = 157.08 rad/s, N = number of turns of coil = 250, A = area of coil = πr² where r = radius of coil = 10 cm = 0.10 m,
A = π(0.1 m)² = 0.03142 m² and B = magnetic field strength
So,
B = ε/ωNA
substituting the values of the variables into the equation given that ε = 17 V
So, B = ε/ωNA
B = 17 V/(157.08 rad/s × 250 turns × 0.03142 m²)
B = 17 V/(1233.8634 rad-turns-m²/s)
B = 0.01378 T
B = 13.78 mT
Answer:
120 kg m/s
Explanation:
The magnitude of the momentum of an object is given by
where
m is the mass of the object
v is its speed
For the block in this problem,
m = 10.0 kg (mass of the block)
v = 12.0 m/s (speed of the block)
Therefore the magnitude of the block's momentum is
D. distance
A light-year is the distance light would travel in 1 year.
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