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kenny6666 [7]
3 years ago
9

When Ethyl Acetoacetate is treated with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol, a compound is produced tha

t has the formula C9H14O3. This compound has an infrared spectrum that shows only one carbonyl adsorption and no OH bond stretch. Suggest a structure for this compound, and provide a mechanism for its formation.
Chemistry
1 answer:
victus00 [196]3 years ago
6 0

Answer:

The reaction of ethyl acetoacetate with 1,3-Dibromopropane and 2 moles of Sodium Ethoxide in Ethanol.

Explanation:

The structure of ethyl acetoacetate is shown below:

The structure of 1,3-dibromopropane is shown below:

Ethyl acetoacetate on reaction with sodium ethoxide in ethanol forms a carbanion intermediate and the formation of carbanion takes place twice and form a cyclic ring.

The entire reaction is shown below:

The structure of C9H14O3 is shown in the chemical reaction that is shown below:

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A chemist makes a solution of NaOH for use in an experiment. She dissolves 0.00500 mol NaOH in 1.00 L H2O. The NaOH completely d
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Answer:

pH = 11.7

Explanation:

<u>Given:</u>

[OH-] = 0.00500 M

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pH of the solution

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