Complete the hybridization and bonding scheme for xef4.
1 answer:
<span>Xe = VIII = 8 valence electrons
F = VII = 4 (7 ve) = 28 valence electrons</span>
total ve = 8 + 28 = 36 ve
<span>36 - 4(2) = 28 ve
(there are 2 electrons in each bond x 4 bonds)</span>
<span>28 - 4(6) = 4
(We assign the remaining electrons to F atoms)</span>
<span>4 - 2(2) = 0
(Therefore 4 electrons left => we have 2 lone pairs)</span>
The steric number = No. of σ bonds + #lone pairs
= 4 σ bonds + 2 lone pairs = 6 => d²sp³ (6 hybrid orbitals)
<span>4 bonds + 2 lone pairs => square planar</span>
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The average atomic mass of the imaginary element : 47.255 amu
<h3>Further explanation </h3>The elements in nature have several types of isotopes
Isotopes are elements that have the same Atomic Number (Proton)
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% ..
isotope E-47 47.011 amu, 87.34%
isotope E-48 48.008 amu, 6.895
isotope E-49 50.009 amu, 5.77%
The average atomic mass :
15.3 litres of water will be produced if we take 1.7 litres of Hydrogen
Explanation:
Let's take a look over synthesis reaction;
<u> </u>
<u />
<u>Balancing the chemical reaction;</u>
<u> </u>
<u />
Thus, 2 moles of hydrogen molecules are required to form 2 moles of water molecules.
<u>Equating the molarity;</u>
<u /> =
(Since, the molecular mass of hyd and water is 2 and 18 respectively)
x=
x= 15.3 litres.
Thus,15.3 L of water will be produced if we take 1.7 litres of Hydrogen in a synthesis reaction.