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Nadya [2.5K]
3 years ago
13

How does the energy of the atoms in a hot cup of coffee compare to the energy of the atoms in a piece of ice?

Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

The atoms in the cup of coffee have more energy.

Explanation:

The difference between the hot cup of coffee and the piece of ice is their temperature. The hot cup of coffee has a higher temperature than the ice.

The relationship between the energy and temperature is a direct relationship. This means that higher temperature means higher kinetic energy and vice versa.

Since the hot cup of coffee has  a higher temperature, it means it also have the highest amount of energy. The correct option is;

The atoms in the cup of coffee have more energy.

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2. A chemical analysis of a sample provides the following elemental data:
Vadim26 [7]

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

3 0
2 years ago
Matthew was working with different concentrations of hydrochloric acid in the lab. Which of these would BEST describe the result
nevsk [136]

The answer to this question would be C. I hope this helps!

7 0
3 years ago
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A neutral atom has an atomic number of 20 and a mass number of 42. How many electrons does the atom have?
Bingel [31]

If we have a neutral atom, then it has the same number protons and neutrons.

The number protons and neutrons for neutral atom shows atomic number.

"A neutral atom has an atomic number of 20" means that atom has 20 protons (that give charge "+ 20" ) and 20 electrons (that give charge "-20").

Answer is 20 electrons.


6 0
3 years ago
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Silicon has a relatively large latent heat of vaporization of 12800 J/g. This indicates that silicon has:
Lesechka [4]

strong attraction between liquid particles

7 0
3 years ago
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The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
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