All categories

3 years ago

How does the energy of the atoms in a hot cup of coffee compare to the energy of the atoms in a piece of ice?

Chemistry

1 answer:

Nonamiya [84]3 years ago

5 0

Answer:

The atoms in the cup of coffee have more energy.

Explanation:

The difference between the hot cup of coffee and the piece of ice is their temperature. The hot cup of coffee has a higher temperature than the ice.

The relationship between the energy and temperature is a direct relationship. This means that higher temperature means higher kinetic energy and vice versa.

Since the hot cup of coffee has a higher temperature, it means it also have the highest amount of energy. The correct option is;

The atoms in the cup of coffee have more energy.

You might be interested in

_______ is a physical property

VMariaS [17]

Answer:

C. Density

all the others are chemical properties

4 0

3 years ago

Read 2 more answers

4 main parts of a flower Include the function of each pls help me

ZanzabumX [31]

Answer:

Calyx or sepals
Corolla
Androecium
Gynoecium

6 0

3 years ago

Place the following in order of decreasing radius. Te2- F- O2-

notka56 [123]

Answer:

Option 2 is correct.

6 0

2 years ago

PLEASE HELP! 25 POINTS!!!! I got the #1, just not #2 and #3. An industrial chemical company has opened a new plant that will pro

podryga [215]

Answer :

Part 1 : Balanced reaction, $3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

Part 2 : The theoretical yield of $NH_3$ gas = 440.96 g

Part 3 : The % yield of ammonia is 90.03 %

Solution : Given,

Mass of $N_2$ = 475 g

Molar mass of $N_2$ = 28 g/mole

Molar mass of $NH_3$ = 17 g/mole

Experimental yield of $NH_3$ = 397 g

Answer for Part (1) :

The balanced chemical reaction is,

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

Answer for Part (2) :

First we have to calculate the moles of $N_2$ .

$\text{Moles of }N_2=\frac{\text{ Mass of }N_2}{\text{ Molecular mass of }N_2}=\frac{475g}{28g/mole}=16.96moles$

From the given reaction, we conclude that

1 moles of $N_2$ gas react to give 2 moles of $NH_3$ gas

16.96 moles of $N_2$ gas react to give $\frac{2}{1}\times 16.96=33.92$ moles of $NH_3$ gas

Now we have to calculate the mass of $NH_3$ gas.

$\text{ Mass of }NH_3=\text{ Moles of }NH_3\times \text{ Molar mass of }NH_3$

$\text{ Mass of }NH_3=(33.92moles)\times (17g/mole)=440.96g$

Therefore, the theoretical yield of $NH_3$ gas = 440.96 g

Answer for Part (3) :

Formula used for percent yield :

$\% \text{ yield of }NH_3=\frac{\text{ Experimental yield of }NH_3}{\text{ Theoretical yield of }NH_3}\times 100$

$\% \text{ yield of }NH_3=\frac{397g}{440.96g}\times 100=90.03\%$

Therefore, the % yield of ammonia is 90.03 %

3 0

3 years ago

The amount of water vapor in a given volume of air is ______________ .The amount of water vapor in the air at any one time depen

Eduardwww [97]

Answer:

The amount of water vapor in a given volume of air is humidity.The amount of water vapor in the air at any one time depends on temperature . Warmer air holds more water than cooler air. Clouds form when humidity is low and thetemperature is high . Relative humidity is defined as the amount of water vapor in the air divided by the amount that would have to be present in the same air to form a cloud or condense on a surface. Dew is related to the humidity of the previous day. The air temperature at which water vapor in the air condenses onto cool surfaces is the dew point.

Explanation:

8 0

3 years ago