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Soloha48 [4]
2 years ago
7

When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bon

ded by ________.
Chemistry
1 answer:
Morgarella [4.7K]2 years ago
8 0

Answer:polar covalent bond

Explanation:

Compounds are formed ether by donating, receiving or sharing of electrons making the bonds between them to  be ionic, or covalent .

Now  according to the rule  of type of bond assignment due to electronegativity difference of atoms

---When the  electronegativity difference is less than 0.5,  the bond formed is nonpolar covalent.

---When   the  electronegativity difference is between 0.5 and 1.6, the bond is considered polar covalent

---When  the  electronegativity difference greater than 2.0, then the bond is ionic.

Therefore, When the absolute value of the difference in electronegativity of two adjacent atom in a compound is 1, they are most likely bonded by  polar covalent bond eg HCl bond , CCL4 bond

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How many moles of Ca atoms are in 1 mol of CaSO4?
Galina-37 [17]

Answer:

6.02 x 10²³ atoms

Explanation:

Given parameters:

Number of moles CaSO₄ = 1 mole

Unknown:

Number of Ca atoms in the given compound = ?

Solution:

The given compound is:

          CaSO₄

     1 mole of CaSO₄  is made up of 1 mole of Ca atoms

Now;

   1 mole of any substance contains 6.02 x 10²³ atoms

  1 mole of Ca atoms will also contain 6.02 x 10²³ atoms

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3 years ago
6CO2, 6H2O, and energy are the result of aerobic respiration.
dsp73

Answer:

True

Explanation:

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What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom
Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains 6.022\times 10^{23} atoms

So, 5.5 g of lead contains \frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22} atoms

and,

As, 118.71 g of lead contains 6.022\times 10^{23} atoms

So, 94.5 g of lead contains \frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23} atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%

and,

\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100

\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

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3 years ago
I can't find the density of this question I need help
zaharov [31]
Density is Mass divided by volume.
4 0
3 years ago
How many sig figs are in 0.0003422
Ivenika [448]

Answer:

4

Explanation:

The zeros before a non zero digit do not count as significant figures so there are 4 sig figs in the number

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