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lys-0071 [83]
3 years ago
11

A radio station is giving away a $100 bill to every 30th caller and movie tickets to every 40th caller. Which call will be the f

irst to win both prizes
Mathematics
1 answer:
Ymorist [56]3 years ago
3 0

Answer:

120th caller

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

$100 bill = 30th caller

Movie tickets = 40th caller

So, to find out first to win both prizes, we will use LCM method,

LCM of 30 and 40 =       10 | 30 , 40

                                            | 3    , 4

LCM of 30 and 40 = 10 × 3 × 4 = 120

Hence, 120th caller will be the first to win both prizes.

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Can you abstractly square the number, "0" ?
OLga [1]

Answer: No, you cannot.

Step-by-step explanation: A square number cannot be a perfect number.

The numbers: 0, 1, 5, 14, 30, 55, 91, 140, 204, 285, 385, 506, 650, 819, 1015, 1240, 1496, 1785, 2109, 2470, 2870, 3311, 3795, 4324, 4900, 5525, 6201 are examples of perfect numbers.

4 0
3 years ago
Combine like terms to create an equivalent expression 3.4 - 2.8d + 2.8d - 1.3
zalisa [80]

Answer:

3.4 - 2.8d + 2.8d - 1.3 = 2.1

Step-by-step explanation:

The given expression is 3.4 -2.8d + 2.8d -1.3

Let's see the definition of like terms.

Like terms are the terms having the same variable and the same exponents.

Examples: -3xy, 2xy  and 4y, 5y and -3, 2.

Now let's identify the like terms from the given expression.

3.4 -2.8d + 2.8d -1.3

Here the like terms are -2.8d, +2.8d and 3.4, -1.3

3.4 -2.8d + 2.8d -1.3

= -2.8d + 2.8d + 3.4 - 1.3            [-2.8d + 2.8d = 0] and 3.4 -1.3 = 2.1

= 0 + 2.1

=2.1

The answer is 2.1

6 0
3 years ago
Read 2 more answers
Point T is on line segment \overline{SU} SU . Given ST=12ST=12 and TU=3,TU=3, determine the length \overline{SU}. SU
vova2212 [387]

Answer:

SU = 15

Step-by-step explanation:

Given that,

Point T is on line segment SU. So,

SU = ST + TU

Putting all the values, we get :

SU = 12 + 3

SU = 15

Hence, the length of SU is 15 units.

3 0
3 years ago
In a sample of 42 burritos, we found a sample mean 1.4 lb and assumed that sigma equals.5. In a test of the hypothesis H subscri
Sergio [31]

Answer:

D. 0.9953 (Probability of a Type II error), 0.0047 (Power of the test)

Step-by-step explanation:

Let's first remember that a Type II error is to NOT reject H0 when it is false, and the probability of that occurring is known as β. On the other hand, power refers to the probability of rejecting H0 when it is false, so it can be calculated as 1 - β.

To resolve this we are going to use the Z-statistic:

                                           Z = (X¯ - μ0) / (σ/√n)

where  μ0 = 1.2

            σ = 5

            n = 42

As we can see in part A of the attached image, we have the normal distribution curve representation for this test, and because this is a two-tailed test, we split the significance level of α=0.01 evenly into the two tails, 0.005 in each tail, and if we look for the Z critical value for those values in a standard distribution Z table we will find that that value is 2.576.

Now we need to stablish the equation that will telll us for what values of X¯ will we reject H0.

Reject if:

Z ≤ -2.576                                                          Z ≥ 2.576

We know the equation for the Z-statistic, so we can substitute like follows and resolve.

Reject if:

(X¯ - 1.2) / (5/√42) ≤ -2.576                          (X¯ - 1.2) / (5/√42) ≥ 2.576

X¯ ≤ -0.79                                                         X¯ ≥ 3.19

We have the information that the true population mean is 1.25, so we now for a fact that H0 is false, so with this we can calculate the probability of a Type II error:  P(Do not reject H0 | μ=1.25)

As we can see in part B of the attached image, we can stablish that the type II error will represent the probability of the sample mean (X¯) falling between -0.79 and 3.19 when μ=1.25, and that represents the shaded area. So now we now that we are looking for P(-0.79 < X¯ < 3.19 | μ=1.25).

Because we know the equation of Z, we are going to standardize this as follows:

P ( (-0.79 - 1.25) / (5/√42) < Z <  (3.19 - 1.25) / (5/√42) )

This equals to:

P(-2.64 < Z < 2.51)

If we go and look for the area under the curve for Z positive scores in a normal standart table (part C of attached image), we will find that that area is 0.9940, which represents the probability of a Type II error.

Therefore, the power of the test will be 1-0.9940 = 0.006

If we look at the options of answers we have, there is no option that looks like this results, which means there was a probable redaction error, so we are going to stay with the closest option to these values which is option D.

3 0
3 years ago
Polynomials with the same roots can have different graphs. True? Or false?
Diano4ka-milaya [45]
True.

E.g. (x-1)(x-2) versus 100(x-1)(x-2)

They have same roots of x= 1 or 2, but the second equation is 100 times stretching of the first one vertically
8 0
3 years ago
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