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MAXImum [283]
3 years ago
8

Who invented pc in the world

Engineering
2 answers:
Flauer [41]3 years ago
8 0

Answer:

Charles Babbage was invented

Bezzdna [24]3 years ago
4 0

Answer:

John Blankenbaker he designed it and invented it

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What part connect to the tie rod that helps the brake chamber out that deals with slack adjuster
scoray [572]

Answer:

none

Explanation:

7 0
2 years ago
In manufacturing a particular set of motor shafts, only shaft diameters of between 38.00 and 37.50 mm are usable. If the process
Masteriza [31]

Answer:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

Explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the diameters of a population, and for this case we know the distribution for X is given by:

X \sim N(37.8,0.12)  

Where \mu=37.8 and \sigma=0.12

We are interested on this probability

P(37.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(37.5

And we can find this probability with this difference:

P(-2.5

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-2.5

So then the percentage usable are 94,6%

4 0
3 years ago
The real power delivered by a source to two impedances, ????1=4+????5⁡Ω and ????2=10⁡Ω connected in parallel, is 1000 W. Determi
kirza4 [7]

Answer:

The question is incomplete, below is the complete question

"The real power delivered by a source to two impedance, Z1=4+j5⁡Ω and Z2=10⁡Ω connected in parallel, is 1000 W. Determine (a) the real power absorbed by each of the impedances and (b) the source current."

answer:

a. 615W, 384.4W

b. 17.4A

Explanation:

To determine the real power absorbed by the impedance, we need to find first the equivalent admittance for each impedance.

recall that the symbol for admittance is Y and express as

Y=\frac{1}{Z}

Hence for each we have,  

Y_{1} =1/Zx_{1}\\Y_{1} =\frac{1}{4+j5}\\converting to polar \\  Y_{1} =\frac{1}{6.4\leq 51.3}\\  Y_{1} =(0.16 \leq -51.3)S

for the second impedance we have

Y_{2}=\frac{1}{10}\\Y_{2}=0.1S

we also determine the voltage cross the impedance,

P=V^2(Y1 +Y2)

V=\sqrt{\frac{P}{Y_{1}+Y_{2}}}\\

V=\sqrt{\frac{1000}{0.16+0.1}}\\ V=62v

The real power in the impedance is calculated as

P_{1}=v^{2}G_{1}\\P_{1}=62*62*0.16\\ P_{1}=615W

for the second impedance

P_{2}=v^{2}*G_{2}\\   P_{2}=62*62*0.1\\384.4w

b. We determine the equivalent admittance

Y_{total}=Y_{1}+Y_{2}\\Y_{total}=(0.16\leq -51.3 )+0.1\\Y_{total}=(0.16-j1.0)+0.1\\Y_{total}=0.26-J1.0\\

We convert the equivalent admittance back into the polar form

Y_{total}=0.28\leq -19.65\\

the source current flows is

I_{s}=VY_{total}\\I_{s}=62*0.28\\I_{s}=17.4A

6 0
3 years ago
The entrance of the space module into atmosphere is one of the very critical phases of any space mission. Due to the formation o
Hatshy [7]

Answer:

Check the explanation

Explanation:

The transferred energy calculations can be done using the equation:

This is when:

• power is calculated in watts (W)

• energy is calculated in joules (J)

• time is calculated in seconds (s)

it can also be calculated by utilizing the same equation but with different units:

• when energy is measured in kilowatt-hours (kWh)

• when power is measured in kilowatts (kW)

• and when time is measured in hours (h)

kindly check the comprehensive step by step calculation to the question in the attached images below

5 0
4 years ago
A square isothermal chip is of width w = 5 mm on a side and is mounted in a substrate such that its side and back surfaces are w
nirvana33 [79]

Answer:

Q(h=200)=0.35W

Q(h=3000)=5.25W

Explanation:

first part h=200W/Km^2

we must use the convection heat transfer equation for the chip

Q=hA(Ts-T∞)

h= convective coefficient=200W/m2 K

A=Base*Leght=5mmx5mm=25mm^2

Ts=temperature of the chip=85C

T∞=temperature of coolant=15C

Q=200x2.5x10^-5(85-15)=0.35W

Second part h=3000W/Km^2

Q=3000x2.5x10^-5(85-15)=5.25W

5 0
3 years ago
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