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3 years ago

Please write the following code in Python 3. Also please show all output(s) and share your code.

Engineering

1 answer:

maksim [4K]3 years ago

6 0

Answer:

sum2 = 0

counter = 0

lst = [65, 78, 21, 33]

while counter < len(lst):

sum2 = sum2 + lst[counter]

counter += 1

Explanation:

The counter variable is initialized to control the while loop and access the numbers in lst

While there are numbers in the lst, loop through lst

Add the numbers in lst to the sum2

Increment counter by 1 after each iteration

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What should be given to a customer before doing a repair?

natima [27]

A. I believe, lmk if I’m right

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3 years ago

The ABC Corporation manufactures and sells two products: T1 and T2. 20XX budget for the company is given below:

Sliva [168]

Answer:

The ABC Corporation

a) Total Expected Revenue (in dollars) for 20XX:

Revenue from T1 = 60,000 x $165 = $26,400,000

Revenue from T2 = 40,000 x $250 = $10,000,000

Total Revenue from T1 and T2 = $36,400,000

b) Production Level (in units) for T1 and T2

T1 T2

Total Units sold 160,000 40,000

Add Closing Inventory 25,000 9,000

Units Available for sale 185,000 49,000

less opening inventory 20,000 8,000

Production Level 165,000 units 41,000 units

c) Total Direct Material Purchases (in dollars):

Cost of direct materials used T1 T2

A: (165,000 x 4 x $12) $7,920,000 $2,460,000 (41,000 x 5 x $12)

B: (165,000 x 2 x $5) 1,650,000 615,000 (41,000 x 3 x $5)

C: 0 123,000 (41,000 x 1 x$3)

Total cost $9,570,000 $3,198,000 Total = $12,768,000

Cost of direct per unit = $58 ($9,570,000/165,000) for T1 and $78 ($3,198,000/41,000) for T2

Cost of direct materials used for production $12,768,000

Cost of closing direct materials:

A (36,000 x $12) $432,000

B (32,000 x $5) 160,000

C (7,000 x $3) 21,000 $613,000

Cost of direct materials available for prodn $13,381,000

Less cost of beginning direct materials:

A (32,000 x $12) $384,000

B (29,000 x $5) 145,000

C (6,000 x $3) 18,000 $547,000

Cost of direct materials purchases $12,834,000

d) The Total Direct Manufacturing Labor Cost (in dollars):

T1 T2

Direct labor per unit 2 hours 3 hours

Direct labor rate per hour $12 $16

Direct labor cost per unit $24 $48

Production level 165,000 units 41,000 units

Labor Cost ($) $3,960,000 $1,968,000

Total labor cost $5,928,000 ($3,960,000 + $1,968,000)

e) Total Overhead cost (in dollars):

Overhead rate = $20 per labor hour

Overhead cost per unit: T1 = $40 ($20 x 2) and T2 = $60 ($20 x 3)

T1 overhead = $20 x 2 x 165,000) = $6,600,000

T2 overhead = $20 x 3 x 41,000) = $2,460,000

Total Overhead cost = $9,060,000

Cost of goods produced:

Cost of opening inventory of materials = $547,000

Purchases of directials materials 12,834,000

less closing inventory of materials = $613,000

Cost of materials used for production 12,768,000

add Labor cost 5,928,000

add Overhead cost 9,060,000

Total production cost $27,756,000

f) Total cost of goods sold (in dollars):

Cost of opening inventory = $3,928,000

Total Production cost = $27,756,000

Cost of goods available for sale $31,684,000

Less cost of closing inventory $4,724,000

Total cost of goods sold $26,960,000

g) Total expected operating income (in dollars)

Sales Revenue: T1 and T2 $36,400,000

Cost of goods sold 26,960,000

Gross profit $9,440,000

less marketing & distribution 400,000

Total Expected Operating Income = $9,040,000

Explanation:

a) Cost of beginning inventory of finished goods:

T1, (Direct materials + Labor + Overhead) X inventory units =

T1 = 20,000 x ($58 + 24 + 40) = $2,440,000

T2 = 8,000 ($78 + 48 + 60) = $1,488,000

Total cost of beginning inventory = $3,928,000

b) Cost of closing Inventory of finished goods:

T1 = 25,000 x ($58 + 24 + 40) = $3,050,000

T2 = 9,000 ($78 + 48 + 60) = $1,674,000

Total cost of closing inventory = $4,724,000

5 0

3 years ago

How many ase certifications are there for automotive technicians?

romanna [79]

Answer:

There are 50 ASE certification tests, covering almost every imaginable aspect of the automotive repair and service industry.

Explanation:

yww <33

5 0

3 years ago

Which of the following ranges depicts the 2% tolerance range to the full 9 digits provided?

Lyrx [107]

Answer:

the only one that meets the requirements is option C .

Explanation:

The tolerance of a quantity is the maximum limit of variation allowed for that quantity.

To find it we must have the value of the magnitude, its closest value is the average value, this value can be given or if it is not known it is calculated with the formula

x_average = ∑ $x_{i}$ / n

The tolerance or error is the current value over the mean value per 100

Δx₁ = x₁ / x_average

tolerance = | 100 -Δx₁ 100 |

bars indicate absolute value

let's look for these values for each case

x_average = (2.1700000+ 2.258571429) / 2

x_average = 2.2142857145

fluctuation for x₁

Δx₁ = 2.17000 / 2.2142857145

Tolerance = 100 - 97.999999991

Tolerance = 2.000000001%

fluctuation x₂

Δx₂ = 2.258571429 / 2.2142857145

Δx2 = 1.02

tolerance = 100 - 102.000000009

tolerance 2.000000001%

x_average = (2.2 + 2.29) / 2

x_average = 2,245

fluctuation x₁

Δx₁ = 2.2 / 2.245

Δx₁ = 0.9799554

tolerance = 100 - 97,999

Tolerance = 2.00446%

fluctuation x₂

Δx₂ = 2.29 / 2.245

Δx₂ = 1.0200445

Tolerance = 2.00445%

x_average = (2.211445 +2.3) / 2

x_average = 2.2557225

Δx₁ = 2.211445 / 2.2557225 = 0.9803710

tolerance = 100 - 98.0371

tolerance = 1.96%

Δx₂ = 2.3 / 2.2557225 = 1.024624

tolerance = 100 -101.962896

tolerance = 1.96%

x_average = (2.20144927 + 2.29130435) / 2

x_average = 2.24637681

Δx₁ = 2.20144927 / 2.24637681 = 0.98000043

tolerance = 100 - 98.000043

tolerance = 2.000002%

Δx₂ = 2.29130435 / 2.24637681 = 1.0200000017

tolerance = 2.0000002%

x_average = (2 +2,3) / 2

x_average = 2.15

Δx₁ = 2 / 2.15 = 0.93023

tolerance = 100 -93.023

tolerance = 6.98%

Δx₂ = 2.3 / 2.15 = 1.0698

tolerance = 6.97%

Let's analyze these results, the result E is clearly not in the requested tolerance range, the other values may be within the desired tolerance range depending on the required precision, for the high precision of this exercise the only one that meets the requirements is option C .

4 0

3 years ago

If you are driving down to the sleep downgrade and you have reached the speed of 40 mph , you would apply the setrvice break unt

bezimeni [28]

Answer:

35 miles

Explanation:

When you are driving a truck that has an air brake system you have to keep in mind that when driving down a steep downgrade, the truck will automatically accelerate due to the inclination of the road, so in order to keep the speed to a controllable situation, you need to activate the service brake until you've reached the 35 miles per hour mark.

4 0

3 years ago