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N76 [4]
3 years ago
5

Convection currents in Earth's mantle are caused by the rise of hot material rising towards the crust, becoming cooler and sinki

ng back down. This process occurs repeatedly, causing the currents to constantly flow. The movement of the currents plays a factor in the movement of the mantle.
Chemistry
1 answer:
lana66690 [7]3 years ago
4 0

Answer:

True or False

Answer - True

Explanation:

The mantle convection clearly describes how the mantle moves, transferring heat from the white-hot core to the lithosphere. The mantle is usually being heated below and the cooling happens above and the general temperature of the area gets dropped over a long period of time.  

Hot buoyant Magma is being transferred through convection currents, to the lithosphere at the plate boundaries and hot spots. Also, convection current moves cooler materials from the crust to the interior of the earth through a process that is widely known as subduction.

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Which of the following provides the most evidence for the theory of plate tectonics? A. the spreading of the sea floor B. the co
malfutka [58]

Answer: the correct answer is a.

Explanation: a spreading of the sea floor is the correct answer.

3 0
3 years ago
A lab scientist cools a liquid sample of water (2.6 kg) at 0.00°C to -192°C. The water turns to ice as this temperature change o
soldier1979 [14.2K]

<u>Answer:</u> The heat released for the given process is -1892 kJ

<u>Explanation:</u>

The processes involved in the given problem are:

1.)H_2O(l)(0^oC,273K)\rightarrow H_2O(s)(0^oC,273K)\\2.)H_2O(s)(0^oC,273K)\rightarrow H_2O(s)(-192^oC,81K)

Pressure is taken as constant.

To calculate the amount of heat released at same temperature, we use the equation:

q=m\times L_{f,v}       ......(1)

where,

q = amount of heat released = ?

m = mass of water/ice

L_{f,v} = latent heat of fusion or vaporization

To calculate the amount of heat released at different temperature, we use the equation:

q=m\times C_{p,m}\times (T_{2}-T_{1})        .......(1)

where,

q = amount of heat released = ?

C_{p,m} = specific heat capacity of medium

m = mass of water/ice

T_2 = final temperature

T_1 = initial temperature

Calculating the heat absorbed for each process:

  • <u>For process 1:</u>

Converting the latent heat of fusion in J/kg, we use the conversion factor:

1 kJ = 1000 J

So, (\frac{-334kJ}{1kg})\times (\frac{1000J}{1kJ})=-334\times 10^3J/kg

We are given:

m=2.6kg\\L_f=-334\times 10^3J/kg

Putting values in equation 1, we get:

q_1=2.6kg\times (-334\times 10^3J/kg)=-868400J

  • <u>For process 2:</u>

We are given:

m=2.6kg\\C_{p,s}=2050J/kg.K\\T_1=273K\T_2=81K

Putting values in equation 2, we get:

q_2=2.6kg\times 2050J/kg.K\times (81-(273))^oC\\\\q_2=1023360J

Total heat absorbed = q_1+q_2

Total heat absorbed = [-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ

Hence, the heat released for the given process is -1892 kJ

3 0
3 years ago
What is the mass of 3.01 x 10^21 atoms of Co
OlgaM077 [116]

Answer:

0.295 g Co

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

3.01 × 10²¹ atoms Co

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Co - 58.93 g/mol

<u>Step 3: Convert</u>

<u />3.01 \cdot 10^{21} \ atoms \ Co(\frac{1 \ mol \ Co}{6.022 \cdot 10^{23} \ atoms \ Co} )(\frac{58.93 \ g \ Co}{1 \ mol \ Co} ) = 0.294552 g Co

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

0.294552 g Co ≈ 0.295 g Co

5 0
3 years ago
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Vedmedyk [2.9K]

The answer is actually D. The pH of the products can be different from the pH of the reactants. Hope this helps :)

8 0
4 years ago
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Which statement describes how a basic coffee cup calorimeter works? A) It measures the mass of a substance given the specific he
fomenos
A calorimeter experiment is a set-up that provides insulation so that no heat escapes to the surroundings and all energy can be accounted for. It can be done at either constant volume or constant pressure. So, the answer to this is knowing the mass of water, the specific heat which is an empirical data, and the change in temperature which can be measured using a thermometer. This experiment could measure the mass of an unknown substance added or the specific heat of the substance or the calorimeter. <em>The answer is D.</em>
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3 years ago
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