<u>Answer:</u> The heat released for the given process is -1892 kJ
<u>Explanation:</u>
The processes involved in the given problem are:

Pressure is taken as constant.
To calculate the amount of heat released at same temperature, we use the equation:
......(1)
where,
q = amount of heat released = ?
m = mass of water/ice
= latent heat of fusion or vaporization
To calculate the amount of heat released at different temperature, we use the equation:
.......(1)
where,
q = amount of heat released = ?
= specific heat capacity of medium
m = mass of water/ice
= final temperature
= initial temperature
Calculating the heat absorbed for each process:
Converting the latent heat of fusion in J/kg, we use the conversion factor:
1 kJ = 1000 J
So, 
We are given:

Putting values in equation 1, we get:

We are given:

Putting values in equation 2, we get:

Total heat absorbed = 
Total heat absorbed = ![[-868400+(-1023360)]J=-1891760J=-1891.76kJ\approx -1892kJ](https://tex.z-dn.net/?f=%5B-868400%2B%28-1023360%29%5DJ%3D-1891760J%3D-1891.76kJ%5Capprox%20-1892kJ)
Hence, the heat released for the given process is -1892 kJ