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2 years ago

6

Deshocribe how you could separate and purify compound A from a mixture of two neutral compounds (A and B) when A comprises 95% o

f the total and B the other 5% of the total. Assume that A and B have similar polarities.

1 answer:

uranmaximum [27]2 years ago

3 0

Answer:

Good Luck!

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The following equation shows the correct molecules formed in the reaction, but the products are incorrect. CH4 +202=H20+ CO2 How

Hunter-Best [27]

For the equation to balance out, you would need 2 H2O on the product. That will give a total of 1 Carbon, 4 Hydrogens and 4 Oxygens on each side.

5 0

3 years ago

Which answer below is not an indication that a chemical reaction has occurred?

ankoles [38]

Only when there is no product that is when a chemical reaction has not occured

4 0

3 years ago

A student obtains the following data: Mass of empty, dry graduated cylinder: 21.577 g Volume added of NaCl solution: 4.602 mL Ma

klasskru [66]

<u>Answer:</u> The density of NaCl solution is 3.930 g/mL

<u>Explanation:</u>

We are given:

Mass of cylinder, $m_1$ = 21.577 g

Mass of NaCl and cylinder combined, M = 39.664 g

Mass of NaCl, $m_2$ = $(M-m_1)=(39.664-21.577)g=18.087g$

To calculate density of a substance, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

We are given:

Mass of NaCl = 18.087 g

Volume of NaCl solution = 4.602 mL

Putting values in above equation, we get:

$\text{Density of NaCl}=\frac{18.087g}{4.602mL}\\\\\text{Density of NaCl}=3.930g/mL$

Hence, the density of NaCl solution is 3.930 g/mL

7 0

2 years ago

Draw the curved arrows to show the mechanism for the reaction of butanedioic (succinic) anhydride with methanol.

Marta_Voda [28]

Here is the mechanism of said reaction.

8 0

3 years ago

What is the number of molecules of c2h5oh in a 3m solution that contains 4.00kg h2o?

Veronika [31]

The number of C2H5OH in a 3 m solution that contain 4.00kg H2O is calculate as below

M = moles of the solute/Kg of water

that is 3M = moles of solute/ 4 Kg
multiply both side by 4

moles of the solute is therefore = 12 moles

by use of Avogadro law constant

1 mole =6.02 x10^23 molecules

what about 12 moles

=12 moles/1 moles x 6.02 x10^23 = 7.224 x10^24 molecules

3 0

3 years ago