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3 years ago

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Deshocribe how you could separate and purify compound A from a mixture of two neutral compounds (A and B) when A comprises 95% o

f the total and B the other 5% of the total. Assume that A and B have similar polarities.

1 answer:

uranmaximum [27]3 years ago

3 0

Answer:

Good Luck!

<em>Follow m</em>e

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Define the term macromolecule

makkiz [27]

Explanation:

a molecule containing a very large number of atoms, such as a protein, nucleic acid, or synthetic polymer.

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3 years ago

Toothpaste is an alkali. How could you use the toothpaste to show that red cabbage is an indicator?

Alecsey [184]

Answer:

PUT THE TOOTHPAST ON CABBAGE AND CHECK IT OUT AFTER A DAY

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2 years ago

If a patient has a medical condition that causes his cells to absorb fewer than normal molecules, this patient would likely feel

Svetach [21]

Answer:oxygen Explanation:The medical condition described here is anaemia. It is a blood cell disorder whereby the red blood cell doesn't function properly and hence doesn't carry enough oxygen to the tissues. This is usually caused when ones body is deficient of iron.The symptoms that may occur to such patients are weakness, fatigue, headache and pale skin.Based on the explanation, the answer is oxygen

Explanation:

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2 years ago

If a radioactive isotope has a half-life of 26.5 days, how many days does it take for a sample of the isotope to decrease by 35.

dangina [55]

Answer:

16.5 days

Explanation:

Given that:

Half life = 26.5 days

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{26.5}\ days^{-1}$

The rate constant, k = 0.02616 days⁻¹

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given:

35.0 % is decomposed which means that 0.35 of $[A_0]$ is decomposed. So,

$\frac {[A_t]}{[A_0]}$ = 1 - 0.35 = 0.65

t = 7.8 min

$\frac {[A_t]}{[A_0]}=e^{-k\times t}$

$0.65=e^{-0.02616\times t}$

<u>t = 16.5 days.</u>

7 0

3 years ago

Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th

arsen [322]

Answer:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

Explanation:

For a weak organic base, the formula to find $p^{OH}$ is given by:

$p^{OH}=p^{K_b}+\log c$

where c is the concentration of base.

Here c= $5\times10^{-3}\ M$

$p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05$

Substituting the above values in the formula,we get:

$p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L$

Hence:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

7 0

3 years ago