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uysha [10]
3 years ago
6

Deshocribe how you could separate and purify compound A from a mixture of two neutral compounds (A and B) when A comprises 95% o

f the total and B the other 5% of the total. Assume that A and B have similar polarities.
Chemistry
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

Good Luck!

<em>Follow m</em>e

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En tu cuaderno, realiza una ficha informativa sobre cómo podrían aplicar los cálculos estequiométricos para la estandarización d
Zanzabum
<h2>Espero Haberte ayudado Eee</h2><h2></h2>

4 0
3 years ago
How many moles of copper are present in 75.0g Cu? Show your complete calculation and give the answer in the correct number of si
velikii [3]

Answer:

The answer to your question is 1.2 moles of copper

Explanation:

Data

mass of copper = 75 g

moles = ?

Process

1.- Look in the periodic table for the atomic mass of copper.

Atomic mass = 63.55 g/mol

2.- Use proportions to determine the moles of copper in 75 g

                          63.55 g of copper -------------------- 1 mol

                          75 g of copper       --------------------  x

Use cross multiplication

                          x = (75 x 1) / 63.55

                          x = 75 / 63.55

                          x = 1.18 moles ≈ 1.2 moles of copper

3 0
4 years ago
Read 2 more answers
Chemical equations need to be balanced in order to satisfy the law of
cupoosta [38]
To satisfy the law of conservation of mass
3 0
4 years ago
Read 2 more answers
49.2 m = _________ hm
dalvyx [7]
The answer is 0.492 because there are 100 meters in a hectometer, and 49.2/100 is 0.492
4 0
4 years ago
Compounds A and B are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 g of sulf
sukhopar [10]

Answer:

1.5

Explanation:

Given that :

Compound A and B are formed from Sulfur + Oxygen.

Compound A :

6g sulfur + 5.99g Oxygen

Compound B:

8.6g sulfur + 12.88g oxygen

Comparing the ratios :

Compound A:

S : O = 6.00 : 5.99

S/0 = 6.0g S / 5.99g O

Compound B :

S : O = 8.60 : 12.88

S / O = 8.60g S / 12.88g O

Mass Ratio of A / mass Ratio of B

(6.0g S / 5.99g O) ÷ (8.60g S / 12.88g O)

(6.0 g S / 5.99g O) × (12.88g O / 8.60g S)

(6 × 12.88) / (5.99 × 8.60)

= 77.28 / 51.514

= 1.50017

= 1.5

4 0
4 years ago
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