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2 years ago

(help!) What is the relationship between the ratios of the Perimeter and the ratios of the Area?

Mathematics

1 answer:

Papessa [141]2 years ago

4 0

Answer:

4.5 I think

Step-by-step explanation:

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Find the value of each variable in the diagram below. Two choices are correct.

Murljashka [212]

Answer:

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3 years ago

I need 2-4 please & show step by step explanation ( show the work ) please!

Likurg_2 [28]

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Step-by-step explanation:

3 0

3 years ago

On any given day, mail gets delivered by either Alice or Bob. If Alice delivers it, which happens with probability 1/4 , she doe

Troyanec [42]

Answer:

(a) The value of fₓ (9.5) is 0.125.

(b) The value of fₓ (10.5) is 0.50.

Step-by-step explanation:

Let X denote delivery time of the mail delivered by Alice and Y denote delivery time of the mail delivered by Bob.

It i provided that:

$X\sim U(9, 11)\\Y\sim U(10, 12)$

The probability that Alice delivers the mail is, p = 1/4.

The probability that Bob delivers the mail is, q = 3/4.

The probability density function of a Uniform distribution with parameters [a, b] is:

$f(x)=\left \{ {{\frac{1}{b-a};\ a, b>0} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Alice is:

$f(X_{A})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[9, 11]} \atop {0;\ otherwise}} \right.$

The probability density function of the delivery time of Bob is:

$f(X_{B})=\left \{ {{\frac{1}{b-a}=\frac{1}{2};\ [a, b]=[10, 12]} \atop {0;\ otherwise}} \right.$

(a)

Compute the value of fₓ (9.5) as follows:

For delivery time 9.5, only Alice can do the delivery because Bob delivers the mail in the time interval 10 to 12.

The value of fₓ (9.5) is:

$f_{X}(9.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times0)\\=\frac{1}{8}\\=0.125$

Thus, the value of fₓ (9.5) is 0.125.

(b)

Compute the value of fₓ (10.5) as follows:

For delivery time 10.5, both Alice and Bob can do the delivery because Alice's delivery time is in the interval 9 to 11 and that of Bob's is in the time interval 10 to 12.

The value of fₓ (10.5) is:

$f_{X}(10.5)=p.f(X_{A})+q.f(X_B})\\=(\frac{1}{4}\times \frac{1}{2})+(\frac{3}{4}\times\frac{1}{2})\\=\frac{1}{8}+\frac{3}{8}\\=0.50$

Thus, the value of fₓ (10.5) is 0.50.

5 0

3 years ago

What is 12.5% written as a fraction in simplest form

Helga [31]

12.5% goes to .125
so .125 as a fraction is:
$\frac{1}{8}$

7 0

3 years ago

Read 2 more answers

Factors of x3 – 9x2 + 5x – 45 by grouping

kati45 [8]

Important: Use the symbol "^" to denote exponentiation:

x3 – 9x2 + 5x – 45 NO
x^3 – 9x^2 + 5x – 45 YES

Look at the first 2 terms. They can be rewritten as x^2(x-9). Then look at the last 2 terms. They can be rewritten as 5(x-9). So, x-9 is the common factor here. Thus, the original expression becomes:

(x^2-5)(x-9).

Note that x^2-5 can be factored, so that the final 3 factors are:

(x-sqrt(5)), (x+sqrt(5)), (x-9).

8 0

3 years ago