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3 years ago

What idea about work and force does the diagram describe? Explain your answer.

Physics

1 answer:

Misha Larkins [42]3 years ago

5 0

Answer:

W = F*d, where displacement is always in the same direction as the force. The work done by a constant force is proportional to the force applied times the displacement of the object.

Explanation:

F and W are directly proportional to each other, while F and d are indirectly propotional.

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A car speeds up from 0 m/s to 14.0 m/s in 325 s. What is the acceleration?

Anton [14]

Answer: $0.04308 m/s^2$

Explanation: Plug the variables into the equation: $a=\frac{v-v_{0} }{t}$ | $v$ equals initial speed, $v_{0}$ equals final speed and $t$ equals time.

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3 years ago

Question 1

kakasveta [241]

Answer:

W = 600 J

Explanation:

We have,

According to attached figure,

Height of the inclined plane is 60 m

Force acting on the block is 10 N

It is required to find the work must be done against gravity to move it to the top of the incline. The work done is given by :

W = mgh

$W=F\times h\\\\W=10\times 60\\\\W=600\ J$

So, the work done against the gravity is 600 J.

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3 years ago

Difference between relaxation time and collision time?

Black_prince [1.1K]

For the answer to the question above, let us first start with relaxation time. it is the absence of an external electric field, the free electrons in a metallic substance will move in random directions so that the resultant velocity of free electrons in any direction is equal to zero. While the Collision time it is the mean time required for the direction of motion of an individual type particle to deviate through approximately as a consequence of collisions with particles of type.

6 0

3 years ago

Read 2 more answers

A mass of 10 g of oxygen fill a weighted pistonâ€“cylinder device at 20 kPa and 110Â°C. The device is now cooled until the tempe

mezya [45]

Answer:

The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

Explanation:

Given that,

Mass of oxygen = 10 g

Pressure = 20 kPa

Initial temperature = 110°C

Final temperature = 0°C

We need to calculate the change of the volume of the device during this cooling

Using formula of change volume

$\Delta V=V_{2}-V_{1}$

$\Delta V=\dfrac{mR}{P}(T_{2}-T_{1})$

Put the value into the formula

$\Delta V=\dfrac{0.3125\times0.0821}{2.0265\times10^{9}}(383-273)$

$\Delta V=14.297\ L$

$\Delta V=14.3\times10^{-3}\ m^3$

Hence, The change of the volume of the device during this cooling is $14.3\times10^{-3}\ m^3$

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3 years ago

What does an electric circuit mean?

nikitadnepr [17]

Answer: An electric circuit includes a device that gives energy to the charged particles constituting the current, such as a battery or a generator; devices that use current, such as lamps, electric motors, or computers; and the connecting wires or transmission lines.

Explanation: Hope this helped! <3

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3 years ago