(a) The electric flux on left face is 0.24 Vm and on the right face is 1 Vm.
(b) The total flux is 1.24 Vm.
(c) The total amount of charge that is inside the box is 1.1 x 10⁻¹¹ C.
<h3>
Area of the left face</h3>
The area of the left face is calculated as follows;
A1 = 0.03 m x 0.02 m = 0.0006 m²
<h3>Electric flux on the left face</h3>
Ф1 = EA1
Ф1 = (400 V/m)( 0.0006 m²) = 0.24 Vm
Let the dimension of the right face = 5 cm by 2 cm
<h3>Area of the right face</h3>
A2 = 0.05 m x 0.02 m = 0.001 m²
<h3>Electric flux on the right face</h3>
Ф2 = EA2
Ф2 = (1000 V/m)( 0.001 m²) = 1 Vm
<h3>Total flux</h3>
Ф = Ф1 + Ф2
Ф = 0.24 Vm + 1 Vm = 1.24 Vm
<h3>Total charge inside the box</h3>
Ф = Q/ε
Q = εФ
Q = (8.85 x 10⁻¹²)(1.24)
Q = 1.1 x 10⁻¹¹ C
Thus, the electric flux on left face is 0.24 Vm and on the right face is 1 Vm.
The total flux is 1.24 Vm and the total amount of charge that is inside the box is 1.1 x 10⁻¹¹ C.
Learn more about total flux here: brainly.com/question/26289097
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