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Otrada [13]
3 years ago
15

For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?

Chemistry
2 answers:
11Alexandr11 [23.1K]3 years ago
8 0
The sub levels in a energy level specified by 'n' is equal to n.e.g. energy level with n=4 has four sub levels. hope this helps!
jekas [21]3 years ago
6 0
In this question given concerning the atom's electron, the number of energy sublevels present in the principal energy level n = 4 is to be determined. For this matter, it should be remembered that the number of sublevels of a certain principal energy level is equal to n. For this item, the number of sublevels is also 4. That is s, p, d and f.
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Greeley [361]

Answer:

Explanation:

Option B volume is the correct answer

5 0
2 years ago
How many lead atoms are in a cube of lead that has a volume of 2.18 cm3 if the density of lead is 11.3 g/cm3?
Anit [1.1K]
10000000.................
3 0
3 years ago
Which half-reaction is most easily reduced? Al3+ + 3e- Al = -1.66 V Cu2+ + 2e- Cu = 0.34 V Fe3+ + e- Fe2+ = 0.77 V Na+ + e- Na =
Rom4ik [11]
<span />The answer is <span>Fe3+ + e- Fe2+ =</span>
6 0
3 years ago
Read 2 more answers
Oftentimes solubility of a compound limits the concentration of the solution that can be prepared. Use the solubility data given
bulgar [2K]

Answer:

NaNO3 (solubility = 89.0 g/100 g H2O)

Explanation:

The solubility of a specie is the amount of solute that will dissolve in one litre of the solvent. Solubility is usually expressed in units of molarity.

Now let us calculate the molarity of the NaNO3 (solubility = 89.0 g/100 g H2O)

Molar mass of NaNO3= 23+14+3(16)= 85gmol-1

Mass of solute=89.0g

Amount of solute= mass of NaNO3/molar mass of NaNO3

Amount of solute= 89.0g/85.0 gmol-1

= 1.0moles of NaNO3

Note that 100g of water=100cm^3 of water.

If 1.0 moles of NaNO3 dissolve in 100cm^3 or water therefore,

x moles of NaNO3 will dissolve in 1000cm^3 of water

x= 1.0 × 1000/ 100

x= 10.0 moles of NaNO3

3 0
3 years ago
A balance reads an object A to be 45.1 kg. The balance reads another object B to be 33.46 kg. What is the total weight of both o
postnew [5]

Answer:

The total weight of both object is 78.56 kg.

Explanation:

Given data:

Mass of object A = 45.1 kg

Mass of object B = 33.46 kg

Total weight of object = ?

Solution:

Total weight of both subject must be the sum of weight of object A and B.

Total weight of objects = weight of object A + weight of object B

Now we will put the values of mass of object A and B.

Total weight of objects = 45.1 kg + 33.46 kg

Total weight of objects =78.56 kg

Thus the total weight of both object is 78.56 kg.

7 0
3 years ago
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