Answer:
2 KCIO₃ → 2 KCI + 3 O₂
Explanation:
A chemical equation is balanced when the number of atoms of each element is equal on both sides of the equation.
You have already identified the initial number of atoms of each element on both sides of the equation. As a rule of thumb, we balance the number of oxygen and hydrogen atoms last.
However, since all the other elements are already balanced, we shall start by balancing the number of oxygen atoms.
The lowest common multiple of 2 and 3 is 6. Thus, we shall ensure that both sides of the equation has 6 oxygen atoms.
2 KCIO₃ → KCI + 3 O₂
<u>Reactants</u>
K --- 2
C--- 2
I --- 2
O --- 6
<u>Products</u>
K --- 1
C --- 1
I --- 1
O --- 6
Notice that number of K, C and I atoms on the left-hand side of the equation has also changed.
2 KCIO₃ → 2 KCI + 3 O₂
<u>Reactants</u>
K --- 2
C --- 2
I --- 2
O --- 6
<u>Products</u>
K --- 2
C --- 2
I --- 2
O --- 6
The equation is now balanced.
Answer:
At end point there will a transition from pink to colorless.
Explanation:
As the student put the vinegar in the titrator and NaOH in the beaker, it means that he has poured phenolphthalein in the NaOH solution.
The pH range of phenolphthalein is 8.3-10 (approx), it means it will show pink color in basic medium.
So on addition of phenolphthalein in NaOH the solution will become pink in color.
When we start pouring vinegar from titrator neutralization of NaOH will begin.
On complete neutralization , on addition of single drop of vinegar the solution will become acidic and there will be complete disappearance of pink color solution in the beaker.
