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SOVA2 [1]
4 years ago
6

A bucket of water contains 5.45 L of water, how many mL of water is this ?

Chemistry
1 answer:
nalin [4]4 years ago
6 0
Answer: It is 5450 mL


Explanation: There are 1000 mL in every L and then there is an extra 450 so just add that at the end
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Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2
erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0
3 years ago
In an aqueous solution at 25°C, if [H30+] = 3.3 * 10^4 M, then [OH-] is:
sleet_krkn [62]

Answer:

[OH-] = 3.0 x 10^-19 M

Explanation:

[H3O+][OH-] = Kw

Kw = 1.0 x 10^-14

[H3O+][OH-] = 1.0 x 10^-14

[OH-] = 1.0 x 10^-14 / 3.3 x 10^4 = 3.0 x 10^-19

3 0
3 years ago
Anyone here im getting bored feel​
xxTIMURxx [149]

Yeah im here and i am alos getting bored to

what are you doing and how is your day ?

5 0
3 years ago
Read 2 more answers
Which is the balanced chemical equation representing the reaction between barium sulfide and platinum fluoride? BaS + PtF2 BaF2
Svetllana [295]

BAS might be an improperly capitalized: BAs, BaS

PTF2 might be an improperly capitalized: PtF2

BAF2 might be an improperly capitalized: BaF2

PTS might be an improperly capitalized: PtS

8 0
3 years ago
Read 2 more answers
Agustina was standing on the edge of a cliff of unknown height holding a bowling ball. She wanted to find the height of the clif
nlexa [21]

Answer:

433 m

Explanation:

Since the fall represents motion under gravity, we use the equation

s = ut - 1/2gt² where s = height of cliff or distance bowling ball falls through, u = initial velocity of bowling ball = 0 m/s(since it starts from rest), t = time = 9.4 s and g = acceleration due to gravity = -9.8 m/s².

So, substituting the values of the variables into the equation, we have

s = 0 m/s × 9.4 s - 1/2 × 9.8 m/s² × (9.4 s)²

s = 0 m - 1/2 × -9.8 m/s² × 88.36 s²

s = 1/2(865.928 m)

s = 432.964

s ≅ 433 m

5 0
3 years ago
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