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2 years ago

Determine the amplitude or period as requested. Amplitude of y = 1/2 * cos 5x

Mathematics

1 answer:

Maru [420]2 years ago

4 0

Answer:

The amplitude is $\frac{1}{2} = 0.5$

Step-by-step explanation:

Trigonometric function:

A trigonometric function has the following format:

$A\sin{bx}$ or $A\cos[bx}$

In which the amplitude is A and the period is $\frac{2\pi}{b}$

Amplitude of y = 1/2 * cos 5x

The multiplier is 1/2, so this is the amplitude.

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AnnZ [28]

Answer:

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Step-by-step explanation:

Equation C is saying:

total cost = 2.50(number of games) + $10 entery fee

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2 years ago

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jeyben [28]

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2 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

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2 years ago

How many x-intercepts are in the quadratic equation y = 7x2 − 2x − 1

babunello [35]

Answer:

There are 2 x intercepts

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2 years ago

What is the equation of the line with (1,0) and (6,6)?

ch4aika [34]

Answer:

6x -5y = 6

Step-by-step explanation:

You can use the 2-point form of the equation of a line to find it.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (6-0)/(6-1)(x -1) +0

y = 6/5(x -1) . . . . . . point-slope form

y = (6/5)x -6/5 . . . . slope-intercept form

5y = 6x -6

6x -5y = 6 . . . . . . . standard form

7 0

3 years ago